Is csc(θ)= 1/(sin(θ)) ?

The answer to whether csc(θ)= 1/(sin(θ)) is True

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prove csc(θ)= 1/(sin(θ))

prove

csc (θ) = \frac{1}{sin ( θ )}

True

Solution steps

csc (θ) = \frac{1}{sin ( θ )}

Use the basic trigonometric identity:

csc (x) = \frac{1}{sin ( x )}

\Rightarrow True

p ro v e \frac{1}{sin ( θ )} - sin (θ) = cot (θ) cos (θ)

p ro v e \frac{sec ( - x )}{tan ( x ) + cot ( x )} = - sin (- x)

p ro v e \frac{sin ( t )}{1 - cos ( t )} = csc (t) + cot (t)

p ro v e sin (- x) + cot (- x) cos (- x) = - csc (x)

p ro v e coth^{2} (x) - csch^{2} (x) = 1