Is tan^2(θ)+1=sec^2(θ) ?

The answer to whether tan^2(θ)+1=sec^2(θ) is True

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prove tan^2(θ)+1=sec^2(θ)

prove

tan^{2} (θ) + 1 = sec^{2} (θ)

True

Solution steps

tan^{2} (θ) + 1 = sec^{2} (θ)

Use the Pythagorean identity:

tan^{2} (x) + 1 = sec^{2} (x)

\Rightarrow True

p ro v e \frac{cos ( x ) sec ( x )}{tan ( x )} = cot (x)

p ro v e \frac{csc ^{2} ( t )}{cot ( t )} = csc (t) sec (t)

p ro v e \frac{2 cos ( 2 x )}{sin ( 2 x )} = cot (x) - tan (x)

p ro v e cot^{2} (t) - cos^{2} (t) = cot^{2} (t) cos^{2} (t)

p ro v e cot (θ) = \frac{cos ( θ )}{sin ( θ )}