Is 1+tan^2(θ)=sec^2(θ) ?

The answer to whether 1+tan^2(θ)=sec^2(θ) is True

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

prove 1+tan^2(θ)=sec^2(θ)

prove

1 + tan^{2} (θ) = sec^{2} (θ)

True

Solution steps

1 + tan^{2} (θ) = sec^{2} (θ)

Use the Pythagorean identity:

tan^{2} (x) + 1 = sec^{2} (x)

\Rightarrow True

p ro v e \frac{sin ( π - x )}{sin ( x + \frac{π}{2} )} = tan (x)

p ro v e \frac{cos ^{2} ( x )}{1 - sin ( x )} = \frac{csc ( x ) + 1}{csc ( x )}

p ro v e cos (3 x) = cos^{3} (x) - 3 sin^{2} (x) cos (x)

p ro v e (1 + cot^{2} (x)) tan (x) = csc (x) sec (x)

p ro v e sin (a + b) + sin (a - b) = 2 sin (a) cos (b)