Is (sec^2(x))/(2tan(x))=csc(2x) ?

The answer to whether (sec^2(x))/(2tan(x))=csc(2x) is True

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prove (sec^2(x))/(2tan(x))=csc(2x)

prove

\frac{sec ^{2} ( x )}{2 tan ( x )} = csc (2 x)

True

Solution steps

\frac{sec ^{2} ( x )}{2 tan ( x )} = csc (2 x)

Manipulating left side

\frac{sec ^{2} ( x )}{2 tan ( x )}

Express with sin, cos

\frac{sec ^{2} ( x )}{2 tan ( x )}

Use the basic trigonometric identity:

sec (x) = \frac{1}{cos ( x )}

= \frac{( \frac{1}{c o s ( x )} ) ^{2}}{2 tan ( x )}

Use the basic trigonometric identity:

tan (x) = \frac{sin ( x )}{cos ( x )}

= \frac{( \frac{1}{c o s ( x )} ) ^{2}}{2 \cdot \frac{s i n ( x )}{c o s ( x )}}

Simplify

\frac{( \frac{1}{c o s ( x )} ) ^{2}}{2 \cdot \frac{s i n ( x )}{c o s ( x )}} : \frac{1}{2 cos ( x ) sin ( x )}

\frac{( \frac{1}{c o s ( x )} ) ^{2}}{2 \cdot \frac{s i n ( x )}{c o s ( x )}}

Multiply

2 \cdot \frac{sin ( x )}{cos ( x )} : \frac{2 sin ( x )}{cos ( x )}

2 \cdot \frac{sin ( x )}{cos ( x )}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{sin ( x ) \cdot 2}{cos ( x )}

= \frac{( \frac{1}{c o s ( x )} ) ^{2}}{\frac{2 s i n ( x )}{c o s ( x )}}

(\frac{1}{cos ( x )})^{2} = \frac{1}{cos ^{2} ( x )}

(\frac{1}{cos ( x )})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{1 ^{2}}{cos ^{2} ( x )}

Apply rule

1^{a} = 1

1^{2} = 1

= \frac{1}{cos ^{2} ( x )}

= \frac{\frac{1}{c o s ^{2} ( x )}}{\frac{2 s i n ( x )}{c o s ( x )}}

Divide fractions:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{1 \cdot cos ( x )}{cos ^{2} ( x ) sin ( x ) \cdot 2}

Refine

= \frac{cos ( x )}{cos ^{2} ( x ) sin ( x ) \cdot 2}

Cancel the common factor:

cos (x)

= \frac{1}{2 cos ( x ) sin ( x )}

= \frac{1}{2 cos ( x ) sin ( x )}

= \frac{1}{2 cos ( x ) sin ( x )}

Manipulating right side

csc (2 x)

Express with sin, cos

csc (2 x)

Use the basic trigonometric identity:

csc (x) = \frac{1}{sin ( x )}

= \frac{1}{sin ( 2 x )}

= \frac{1}{sin ( 2 x )}

Rewrite using trig identities

\frac{1}{sin ( 2 x )}

Use the Double Angle identity:

sin (2 x) = 2 sin (x) cos (x)

= \frac{1}{2 sin ( x ) cos ( x )}

= \frac{1}{2 sin ( x ) cos ( x )}

We showed that the two sides could take the same form

\Rightarrow True

p ro v e (sec^{2} (x) - 1) csc (x) = tan (x) sec (x)

p ro v e cos (x - \frac{π}{2}) = sin (x)

p ro v e (1 + tan^{2} (x)) cot (x) = sec (x) csc (x)

p ro v e cos (x - y) - cos (x + y) = 2 sin (x) sin (y)

p ro v e (sec (θ) + tan (θ)) (sec (θ) - tan (θ)) = 1

Is (sec^2(x))/(2tan(x))=csc(2x) ?
The answer to whether (sec^2(x))/(2tan(x))=csc(2x) is True