{
"query": {
"display": "$$\\sqrt{3}\\tan\\left(θ\\right)+1=0$$",
"symbolab_question": "EQUATION#\\sqrt{3}\\tan(θ)+1=0"
},
"solution": {
"level": "PERFORMED",
"subject": "Trigonometry",
"topic": "Trig Equations",
"subTopic": "Trig Equations",
"default": "θ=\\frac{5π}{6}+πn",
"degrees": "θ=150^{\\circ }+180^{\\circ }n",
"meta": {
"showVerify": true
}
},
"steps": {
"type": "interim",
"title": "$$\\sqrt{3}\\tan\\left(θ\\right)+1=0{\\quad:\\quad}θ=\\frac{5π}{6}+πn$$",
"input": "\\sqrt{3}\\tan\\left(θ\\right)+1=0",
"steps": [
{
"type": "interim",
"title": "Move $$1\\:$$to the right side",
"input": "\\sqrt{3}\\tan\\left(θ\\right)+1=0",
"result": "\\sqrt{3}\\tan\\left(θ\\right)=-1",
"steps": [
{
"type": "step",
"primary": "Subtract $$1$$ from both sides",
"result": "\\sqrt{3}\\tan\\left(θ\\right)+1-1=0-1"
},
{
"type": "step",
"primary": "Simplify",
"result": "\\sqrt{3}\\tan\\left(θ\\right)=-1"
}
],
"meta": {
"interimType": "Move to the Right Title 1Eq",
"gptData": "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"
}
},
{
"type": "interim",
"title": "Divide both sides by $$\\sqrt{3}$$",
"input": "\\sqrt{3}\\tan\\left(θ\\right)=-1",
"result": "\\tan\\left(θ\\right)=-\\frac{\\sqrt{3}}{3}",
"steps": [
{
"type": "step",
"primary": "Divide both sides by $$\\sqrt{3}$$",
"result": "\\frac{\\sqrt{3}\\tan\\left(θ\\right)}{\\sqrt{3}}=\\frac{-1}{\\sqrt{3}}"
},
{
"type": "interim",
"title": "Simplify",
"input": "\\frac{\\sqrt{3}\\tan\\left(θ\\right)}{\\sqrt{3}}=\\frac{-1}{\\sqrt{3}}",
"result": "\\tan\\left(θ\\right)=-\\frac{\\sqrt{3}}{3}",
"steps": [
{
"type": "interim",
"title": "Simplify $$\\frac{\\sqrt{3}\\tan\\left(θ\\right)}{\\sqrt{3}}:{\\quad}\\tan\\left(θ\\right)$$",
"input": "\\frac{\\sqrt{3}\\tan\\left(θ\\right)}{\\sqrt{3}}",
"steps": [
{
"type": "step",
"primary": "Cancel the common factor: $$\\sqrt{3}$$",
"result": "=\\tan\\left(θ\\right)"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Generic Simplify Specific 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s74DwjiBDVBIb8+yh6fkkMMYmJyq1aLOU5AvxErppUUjhbqvHcXS1YJzMCVe3rDX+wCUCWbkwGOY7PqKo3U/JLJaljYExoPuHUP+srvIBoYoFFKk3fejFkyiOiq9iG9IkAIuSmJUDtLxRPyJ57Nkq7qib97z4ciRBzgXtcnYl8cinMtAjEnFCFc8OXHUm5jgsFMJa9jzdDvGquramb/qO0hA=="
}
},
{
"type": "interim",
"title": "Simplify $$\\frac{-1}{\\sqrt{3}}:{\\quad}-\\frac{\\sqrt{3}}{3}$$",
"input": "\\frac{-1}{\\sqrt{3}}",
"steps": [
{
"type": "step",
"primary": "Apply the fraction rule: $$\\frac{-a}{b}=-\\frac{a}{b}$$",
"result": "=-\\frac{1}{\\sqrt{3}}"
},
{
"type": "interim",
"title": "Rationalize $$-\\frac{1}{\\sqrt{3}}:{\\quad}-\\frac{\\sqrt{3}}{3}$$",
"input": "-\\frac{1}{\\sqrt{3}}",
"result": "=-\\frac{\\sqrt{3}}{3}",
"steps": [
{
"type": "step",
"primary": "Multiply by the conjugate $$\\frac{\\sqrt{3}}{\\sqrt{3}}$$",
"result": "=-\\frac{1\\cdot\\:\\sqrt{3}}{\\sqrt{3}\\sqrt{3}}",
"meta": {
"title": {
"extension": "To rationalize the denominator, multiply numerator and denominator by the conjugate of the radical $$\\sqrt{3}$$"
}
}
},
{
"type": "step",
"primary": "$$1\\cdot\\:\\sqrt{3}=\\sqrt{3}$$"
},
{
"type": "interim",
"title": "$$\\sqrt{3}\\sqrt{3}=3$$",
"input": "\\sqrt{3}\\sqrt{3}",
"result": "=-\\frac{\\sqrt{3}}{3}",
"steps": [
{
"type": "step",
"primary": "Apply radical rule: $$\\sqrt{a}\\sqrt{a}=a$$",
"secondary": [
"$$\\sqrt{3}\\sqrt{3}=3$$"
],
"result": "=3",
"meta": {
"practiceLink": "/practice/radicals-practice",
"practiceTopic": "Radical Rules"
}
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7KTpmXttz9tzhFROsvdfdpl9t0rGzXfqIeCX9GJLyBFHMwViaLUXkeD+JukROhWdjqqRb86vK1jAPxwJmTBc7jxuwBfr4jqpPqXmFXXvxZ1uqe0B1E2GM2M0eTcXoyACf"
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}
],
"meta": {
"interimType": "Rationalize Title 1Eq"
}
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Generic Simplify Specific 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7tkkS6M9CCT9LrMl7pDU/tluq8dxdLVgnMwJV7esNf7AJQJZuTAY5js+oqjdT8kslDa1hUvtzgBcwD7zey8pjX7ynZksDFGW8KDVRRFssbMXWwPs1+Gw97t4MeuaNjSYTwPBBw3byB5RPtpSy6YLt2l15CaX671zydgCHN23vogCJqVxX90jlMfh9fKn6dzC4"
}
},
{
"type": "step",
"result": "\\tan\\left(θ\\right)=-\\frac{\\sqrt{3}}{3}"
}
],
"meta": {
"interimType": "Generic Simplify 0Eq"
}
}
],
"meta": {
"interimType": "Divide Both Sides Specific 1Eq",
"gptData": "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"
}
},
{
"type": "interim",
"title": "General solutions for $$\\tan\\left(θ\\right)=-\\frac{\\sqrt{3}}{3}$$",
"result": "θ=\\frac{5π}{6}+πn",
"steps": [
{
"type": "step",
"primary": "$$\\tan\\left(x\\right)$$ periodicity table with $$πn$$ cycle:<br/>$$\\begin{array}{|c|c|}\\hline x&\\tan(x)\\\\\\hline 0&0\\\\\\hline \\frac{π}{6}&\\frac{\\sqrt{3}}{3}\\\\\\hline \\frac{π}{4}&1\\\\\\hline \\frac{π}{3}&\\sqrt{3}\\\\\\hline \\frac{π}{2}&\\pm\\infty\\\\\\hline \\frac{2π}{3}&-\\sqrt{3}\\\\\\hline \\frac{3π}{4}&-1\\\\\\hline \\frac{5π}{6}&-\\frac{\\sqrt{3}}{3}\\\\\\hline &\\\\\\hline \\end{array}$$"
},
{
"type": "step",
"result": "θ=\\frac{5π}{6}+πn"
}
],
"meta": {
"interimType": "Trig General Solutions tan 1Eq"
}
}
],
"meta": {
"solvingClass": "Trig Equations",
"practiceLink": "/practice/trigonometry-practice#area=main&subtopic=Trig%20Equations",
"practiceTopic": "Trig Equations"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "θ",
"plotRequest": "\\sqrt{3}\\tan(θ)+1"
},
"showViewLarger": true
}
},
"meta": {
"showVerify": true
}
}
Solution
Solution
+1
Degrees
Solution steps
Move to the right side
Subtract from both sides
Simplify
Divide both sides by
Divide both sides by
Simplify
Simplify
Cancel the common factor:
Simplify
Apply the fraction rule:
Rationalize
Multiply by the conjugate
Apply radical rule:
General solutions for
periodicity table with cycle:
Graph
Popular Examples
Frequently Asked Questions (FAQ)
What is the general solution for sqrt(3)tan(θ)+1=0 ?
The general solution for sqrt(3)tan(θ)+1=0 is θ=(5pi)/6+pin