sin(θ)=(150sin(115))/(212.6)

Lösung

sin (θ) = \frac{150 sin ( 11 5 ^{\circ} )}{212.6}

θ = 0.69377 \dots + 36 0^{\circ} n, θ = 18 0^{\circ} - 0.69377 \dots + 36 0^{\circ} n

Radianten

θ = 0.69377 \dots + 2 πn, θ = π - 0.69377 \dots + 2 πn

Schritte zur Lösung

sin (θ) = \frac{150 sin ( 11 5 ^{\circ} )}{212.6}

Wende die Eigenschaften der Trigonometrie an

sin (θ) = \frac{150 sin ( 11 5 ^{\circ} )}{212.6}

Allgemeine Lösung für

sin (θ) = \frac{150 sin ( 11 5 ^{\circ} )}{212.6}

sin (x) = a \Rightarrow x = arcsin (a) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (a) + 36 0^{\circ} n

θ = arcsin (\frac{150 sin ( 11 5 ^{\circ} )}{212.6}) + 36 0^{\circ} n, θ = 18 0^{\circ} - arcsin (\frac{150 sin ( 11 5 ^{\circ} )}{212.6}) + 36 0^{\circ} n

θ = arcsin (\frac{150 sin ( 11 5 ^{\circ} )}{212.6}) + 36 0^{\circ} n, θ = 18 0^{\circ} - arcsin (\frac{150 sin ( 11 5 ^{\circ} )}{212.6}) + 36 0^{\circ} n

Zeige Lösungen in Dezimalform

θ = 0.69377 \dots + 36 0^{\circ} n, θ = 18 0^{\circ} - 0.69377 \dots + 36 0^{\circ} n

2 cos^{2} (2 x) + cos (2 x) - 1 = 0

3 sin (x) + 2 = 1

sin (y) = - 1

cos^{2} (x) - sin^{2} (x) = \frac{1}{2}, 0 \leq x \leq π

cos (θ) = 0.9848