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Popular Trigonometry >

1/(cot(x))-(sec(x))/(csc(x))=cos(x)

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Solution

cot(x)1​−csc(x)sec(x)​=cos(x)

Solution

NoSolutionforx∈R
Solution steps
cot(x)1​−csc(x)sec(x)​=cos(x)
Subtract cos(x) from both sidescot(x)1​−csc(x)sec(x)​−cos(x)=0
Simplify cot(x)1​−csc(x)sec(x)​−cos(x):cot(x)csc(x)csc(x)−sec(x)cot(x)−cos(x)cot(x)csc(x)​
cot(x)1​−csc(x)sec(x)​−cos(x)
Convert element to fraction: cos(x)=1cos(x)​=cot(x)1​−csc(x)sec(x)​−1cos(x)​
Least Common Multiplier of cot(x),csc(x),1:cot(x)csc(x)
cot(x),csc(x),1
Lowest Common Multiplier (LCM)
Compute an expression comprised of factors that appear in at least one of the factored expressions=cot(x)csc(x)
Adjust Fractions based on the LCM
Multiply each numerator by the same amount needed to multiply its
corresponding denominator to turn it into the LCM cot(x)csc(x)
For cot(x)1​:multiply the denominator and numerator by csc(x)cot(x)1​=cot(x)csc(x)1⋅csc(x)​=cot(x)csc(x)csc(x)​
For csc(x)sec(x)​:multiply the denominator and numerator by cot(x)csc(x)sec(x)​=csc(x)cot(x)sec(x)cot(x)​
For 1cos(x)​:multiply the denominator and numerator by cot(x)csc(x)1cos(x)​=1⋅cot(x)csc(x)cos(x)cot(x)csc(x)​=cot(x)csc(x)cos(x)cot(x)csc(x)​
=cot(x)csc(x)csc(x)​−csc(x)cot(x)sec(x)cot(x)​−cot(x)csc(x)cos(x)cot(x)csc(x)​
Since the denominators are equal, combine the fractions: ca​±cb​=ca±b​=cot(x)csc(x)csc(x)−sec(x)cot(x)−cos(x)cot(x)csc(x)​
cot(x)csc(x)csc(x)−sec(x)cot(x)−cos(x)cot(x)csc(x)​=0
g(x)f(x)​=0⇒f(x)=0csc(x)−sec(x)cot(x)−cos(x)cot(x)csc(x)=0
Express with sin, cos
csc(x)−cot(x)sec(x)−cos(x)cot(x)csc(x)
Use the basic trigonometric identity: csc(x)=sin(x)1​=sin(x)1​−cot(x)sec(x)−cos(x)cot(x)sin(x)1​
Use the basic trigonometric identity: cot(x)=sin(x)cos(x)​=sin(x)1​−sin(x)cos(x)​sec(x)−cos(x)sin(x)cos(x)​⋅sin(x)1​
Use the basic trigonometric identity: sec(x)=cos(x)1​=sin(x)1​−sin(x)cos(x)​⋅cos(x)1​−cos(x)sin(x)cos(x)​⋅sin(x)1​
Simplify sin(x)1​−sin(x)cos(x)​⋅cos(x)1​−cos(x)sin(x)cos(x)​⋅sin(x)1​:−sin2(x)cos2(x)​
sin(x)1​−sin(x)cos(x)​⋅cos(x)1​−cos(x)sin(x)cos(x)​⋅sin(x)1​
sin(x)cos(x)​⋅cos(x)1​=sin(x)1​
sin(x)cos(x)​⋅cos(x)1​
Multiply fractions: ba​⋅dc​=b⋅da⋅c​=sin(x)cos(x)cos(x)⋅1​
Cancel the common factor: cos(x)=sin(x)1​
cos(x)sin(x)cos(x)​⋅sin(x)1​=sin2(x)cos2(x)​
cos(x)sin(x)cos(x)​⋅sin(x)1​
Multiply fractions: a⋅cb​⋅ed​=c⋅ea⋅b⋅d​=sin(x)sin(x)cos(x)⋅1⋅cos(x)​
cos(x)⋅1⋅cos(x)=cos2(x)
cos(x)⋅1⋅cos(x)
Apply exponent rule: ab⋅ac=ab+ccos(x)cos(x)=cos1+1(x)=1⋅cos1+1(x)
Refine=cos2(x)
=sin(x)sin(x)cos2(x)​
sin(x)sin(x)=sin2(x)
sin(x)sin(x)
Apply exponent rule: ab⋅ac=ab+csin(x)sin(x)=sin1+1(x)=sin1+1(x)
Add the numbers: 1+1=2=sin2(x)
=sin2(x)cos2(x)​
=sin(x)1​−sin(x)1​−sin2(x)cos2(x)​
Add similar elements: 1⋅sin(x)1​−1⋅sin(x)1​=0=−sin2(x)cos2(x)​
=−sin2(x)cos2(x)​
−sin2(x)cos2(x)​=0
g(x)f(x)​=0⇒f(x)=0−cos2(x)=0
Divide both sides by −1
−cos2(x)=0
Divide both sides by −1
−cos2(x)=0
Divide both sides by −1−1−cos2(x)​=−10​
Simplifycos2(x)=0
cos2(x)=0
Apply rule xn=0⇒x=0
cos(x)=0
General solutions for cos(x)=0
cos(x) periodicity table with 2πn cycle:
x06π​4π​3π​2π​32π​43π​65π​​cos(x)123​​22​​21​0−21​−22​​−23​​​xπ67π​45π​34π​23π​35π​47π​611π​​cos(x)−1−23​​−22​​−21​021​22​​23​​​​
x=2π​+2πn,x=23π​+2πn
x=2π​+2πn,x=23π​+2πn
Since the equation is undefined for:2π​+2πn,23π​+2πnNoSolutionforx∈R

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Popular Examples

sin(x)=1,2pi<= x<= 4pisin(x)=1,2π≤x≤4πcos(a)=1cos(a)=1-cos(x)+1=2sin^2(x)−cos(x)+1=2sin2(x)sec(θ)= 7/5sec(θ)=57​(sin(x))/(cos(x))=0cos(x)sin(x)​=0

Frequently Asked Questions (FAQ)

  • What is the general solution for 1/(cot(x))-(sec(x))/(csc(x))=cos(x) ?

    The general solution for 1/(cot(x))-(sec(x))/(csc(x))=cos(x) is No Solution for x\in\mathbb{R}
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