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受欢迎的三角函数 >

tan(θ+26.565)=(12.5^2)/(9.81(60))

解答

tan (θ + 26.56 5^{\circ}) = \frac{12. 5 ^{2}}{9.81 ( 60 )}

解答

θ = 0.25947 \dots + 18 0^{\circ} n - 26.56500 \dots^{\circ}

+1

弧度

θ = 0.25947 \dots - \frac{571 π}{3869} + πn

求解步骤

tan (θ + 26.56 5^{\circ}) = \frac{12. 5 ^{2}}{9.81 ( 60 )}

化简

\frac{12. 5 ^{2}}{9.81 \cdot 60} : \frac{156.25}{588.6}

\frac{12. 5 ^{2}}{9.81 \cdot 60}

数字相乘:

9.81 \cdot 60 = 588.6

= \frac{12. 5 ^{2}}{588.6}

12. 5^{2} = 156.25

= \frac{156.25}{588.6}

使用反三角函数性质

tan (θ + 26.56500 \dots^{\circ}) = \frac{156.25}{588.6}

tan (θ + 26.56500 \dots^{\circ}) = \frac{156.25}{588.6}

的通解

tan (x) = a \Rightarrow x = arctan (a) + 18 0^{\circ} n

θ + 26.56500 \dots^{\circ} = arctan (\frac{156.25}{588.6}) + 18 0^{\circ} n

θ + 26.56500 \dots^{\circ} = arctan (\frac{156.25}{588.6}) + 18 0^{\circ} n

解

θ + 26.56500 \dots^{\circ} = arctan (\frac{156.25}{588.6}) + 18 0^{\circ} n : θ = arctan (\frac{156.25}{588.6}) + 18 0^{\circ} n - 26.56500 \dots^{\circ}

θ + 26.56500 \dots^{\circ} = arctan (\frac{156.25}{588.6}) + 18 0^{\circ} n

将

26.56500 \dots^{\circ}

到右边

θ + 26.56500 \dots^{\circ} = arctan (\frac{156.25}{588.6}) + 18 0^{\circ} n

两边减去

26.56500 \dots^{\circ}

θ + 26.56500 \dots^{\circ} - 26.56500 \dots^{\circ} = arctan (\frac{156.25}{588.6}) + 18 0^{\circ} n - 26.56500 \dots^{\circ}

化简

θ = arctan (\frac{156.25}{588.6}) + 18 0^{\circ} n - 26.56500 \dots^{\circ}

θ = arctan (\frac{156.25}{588.6}) + 18 0^{\circ} n - 26.56500 \dots^{\circ}

θ = arctan (\frac{156.25}{588.6}) + 18 0^{\circ} n - 26.56500 \dots^{\circ}

以小数形式表示解

θ = 0.25947 \dots + 18 0^{\circ} n - 26.56500 \dots^{\circ}

作图

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