What is the general solution for arccos(x)= 1/2 ?

The general solution for arccos(x)= 1/2 is x=cos(1/2)

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arccos(x)= 1/2

arccos (x) = \frac{1}{2}

x = cos (\frac{1}{2})

Solution steps

arccos (x) = \frac{1}{2}

Apply trig inverse properties

arccos (x) = \frac{1}{2}

arccos (x) = a \Rightarrow x = cos (a)

x = cos (\frac{1}{2})

x = cos (\frac{1}{2})

3 sin^{2} (θ) - 7 sin (θ) + 2 = 0

4 sec^{2} (x) - 2 = 0

cos (x) = \frac{1}{3}

sin (x) cos (x) = \frac{3}{4}, 0 \leq x \leq 2 π

2 cos^{2} (x) + sin (x) - 1 = 0, 0 \leq x < 2 π

What is the general solution for arccos(x)= 1/2 ?
The general solution for arccos(x)= 1/2 is x=cos(1/2)