What is the general solution for sin(2θ)=-0.6 ?

The general solution for sin(2θ)=-0.6 is θ=-(0.64350…)/2+pin,θ= pi/2+(0.64350…)/2+pin

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sin(2θ)=-0.6

sin (2 θ) = - 0.6

θ = - \frac{0.64350 \dots}{2} + πn, θ = \frac{π}{2} + \frac{0.64350 \dots}{2} + πn

Solution steps

sin (2 θ) = - 0.6

Apply trig inverse properties

2 θ = arcsin (- 0.6) + 2 πn, 2 θ = π + arcsin (0.6) + 2 πn

Solve

2 θ = arcsin (- 0.6) + 2 πn : θ = - \frac{arcsin ( \frac{3}{5} )}{2} + πn

Solve

2 θ = π + arcsin (0.6) + 2 πn : θ = \frac{π}{2} + \frac{arcsin ( 0.6 )}{2} + πn

θ = - \frac{arcsin ( \frac{3}{5} )}{2} + πn, θ = \frac{π}{2} + \frac{arcsin ( 0.6 )}{2} + πn

Show solutions in decimal form

θ = - \frac{0.64350 \dots}{2} + πn, θ = \frac{π}{2} + \frac{0.64350 \dots}{2} + πn

cot (θ) = 0

tan (x) = - 3

sin (3 5^{\circ})

sin (\frac{7 π}{4})

cot (\frac{π}{6})

What is the general solution for sin(2θ)=-0.6 ?
The general solution for sin(2θ)=-0.6 is θ=-(0.64350…)/2+pin,θ= pi/2+(0.64350…)/2+pin