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Popular Trigonometry >

solvefor x,cot(-x)cos(-x)+sin(-x)=-1/f

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Solution

solve for x,cot(−x)cos(−x)+sin(−x)=−f1​

Solution

x=arcsin(f)+2πn,x=π+arcsin(−f)+2πn
Solution steps
cot(−x)cos(−x)+sin(−x)=−f1​
Rewrite using trig identities
cot(−x)cos(−x)+sin(−x)=−f1​
−sin(x)+cos(x)(−cot(x))=−f1​
Simplify −sin(x)+cos(x)(−cot(x)):−sin(x)−cos(x)cot(x)
−sin(x)+cos(x)(−cot(x))
Remove parentheses: (−a)=−a=−sin(x)−cos(x)cot(x)
−sin(x)−cos(x)cot(x)=−f1​
−sin(x)−cos(x)cot(x)=−f1​
Subtract −f1​ from both sides−sin(x)−cos(x)cot(x)+f1​=0
Simplify −sin(x)−cos(x)cot(x)+f1​:f−fsin(x)−fcos(x)cot(x)+1​
−sin(x)−cos(x)cot(x)+f1​
Convert element to fraction: sin(x)=fsin(x)f​,cos(x)cot(x)=fcos(x)cot(x)f​=−fsin(x)f​−fcos(x)cot(x)f​+f1​
Since the denominators are equal, combine the fractions: ca​±cb​=ca±b​=f−sin(x)f−cos(x)cot(x)f+1​
f−fsin(x)−fcos(x)cot(x)+1​=0
g(x)f(x)​=0⇒f(x)=0−fsin(x)−fcos(x)cot(x)+1=0
Rewrite using trig identities
1−sin(x)f−cos(x)cot(x)f
Use the basic trigonometric identity: cot(x)=sin(x)cos(x)​=1−sin(x)f−cos(x)sin(x)cos(x)​f
cos(x)sin(x)cos(x)​f=sin(x)fcos2(x)​
cos(x)sin(x)cos(x)​f
Multiply fractions: a⋅cb​=ca⋅b​=sin(x)cos(x)cos(x)f​
cos(x)cos(x)f=fcos2(x)
cos(x)cos(x)f
Apply exponent rule: ab⋅ac=ab+ccos(x)cos(x)=cos1+1(x)=cos1+1(x)f
Add the numbers: 1+1=2=cos2(x)f
=sin(x)fcos2(x)​
=1−fsin(x)−sin(x)fcos2(x)​
Use the Pythagorean identity: cos2(x)+sin2(x)=1cos2(x)=1−sin2(x)=1−sin(x)(1−sin2(x))f​−sin(x)f
Combine the fractions −sin(x)f(−sin2(x)+1)​−fsin(x):−sin(x)f​
−sin(x)f(−sin2(x)+1)​−fsin(x)
Convert element to fraction: fsin(x)=sin(x)sin(x)fsin(x)​=−sin(x)(1−sin2(x))f​−sin(x)sin(x)fsin(x)​
Since the denominators are equal, combine the fractions: ca​±cb​=ca±b​=sin(x)−(1−sin2(x))f−sin(x)fsin(x)​
−(1−sin2(x))f−sin(x)fsin(x)=−f(1−sin2(x))−fsin2(x)
−(1−sin2(x))f−sin(x)fsin(x)
sin(x)fsin(x)=fsin2(x)
sin(x)fsin(x)
Apply exponent rule: ab⋅ac=ab+csin(x)sin(x)=sin1+1(x)=fsin1+1(x)
Add the numbers: 1+1=2=fsin2(x)
=−f(−sin2(x)+1)−fsin2(x)
=sin(x)−f(−sin2(x)+1)−fsin2(x)​
Expand −(1−sin2(x))f−fsin2(x):−f
−(1−sin2(x))f−fsin2(x)
=−f(1−sin2(x))−fsin2(x)
Expand −f(1−sin2(x)):−f+fsin2(x)
−f(1−sin2(x))
Apply the distributive law: a(b−c)=ab−aca=−f,b=1,c=sin2(x)=−f⋅1−(−f)sin2(x)
Apply minus-plus rules−(−a)=a=−1⋅f+fsin2(x)
Multiply: 1⋅f=f=−f+fsin2(x)
=−f+fsin2(x)−fsin2(x)
Add similar elements: fsin2(x)−fsin2(x)=0=−f
=sin(x)−f​
Apply the fraction rule: b−a​=−ba​=−sin(x)f​
1−sin(x)f​=0
1−sin(x)f​=0
Multiply both sides by sin(x)
1−sin(x)f​=0
Multiply both sides by sin(x)1⋅sin(x)−sin(x)f​sin(x)=0⋅sin(x)
Simplify
1⋅sin(x)−sin(x)f​sin(x)=0⋅sin(x)
Simplify 1⋅sin(x):sin(x)
1⋅sin(x)
Multiply: 1⋅sin(x)=sin(x)=sin(x)
Simplify −sin(x)f​sin(x):−f
−sin(x)f​sin(x)
Multiply fractions: a⋅cb​=ca⋅b​=−sin(x)fsin(x)​
Cancel the common factor: sin(x)=−f
Simplify 0⋅sin(x):0
0⋅sin(x)
Apply rule 0⋅a=0=0
sin(x)−f=0
sin(x)−f=0
sin(x)−f=0
Move fto the right side
sin(x)−f=0
Add f to both sidessin(x)−f+f=0+f
Simplifysin(x)=f
sin(x)=f
Apply trig inverse properties
sin(x)=f
General solutions for sin(x)=fsin(x)=a⇒x=arcsin(a)+2πn,x=π+arcsin(a)+2πnx=arcsin(f)+2πn,x=π+arcsin(−f)+2πn
x=arcsin(f)+2πn,x=π+arcsin(−f)+2πn

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