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受欢迎的三角函数 >

cot(2x)=sqrt(3)

解答

cot (2 x) = 3

解答

x = \frac{π}{12} + \frac{πn}{2}

+1

度数

x = 1 5^{\circ} + 9 0^{\circ} n

求解步骤

cot (2 x) = 3

cot (2 x) = 3

的通解

cot (x)

周期表（周期为

πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cot (x) \mp \infty 31 \frac{3}{3} 0 - \frac{3}{3} - 1 - 3

2 x = \frac{π}{6} + πn

2 x = \frac{π}{6} + πn

解

2 x = \frac{π}{6} + πn : x = \frac{π}{12} + \frac{πn}{2}

2 x = \frac{π}{6} + πn

两边除以

2

2 x = \frac{π}{6} + πn

两边除以

2

\frac{2 x}{2} = \frac{\frac{π}{6}}{2} + \frac{πn}{2}

化简

\frac{2 x}{2} = \frac{\frac{π}{6}}{2} + \frac{πn}{2}

化简

\frac{2 x}{2} : x

\frac{2 x}{2}

数字相除:

\frac{2}{2} = 1

= x

化简

\frac{\frac{π}{6}}{2} + \frac{πn}{2} : \frac{π}{12} + \frac{πn}{2}

\frac{\frac{π}{6}}{2} + \frac{πn}{2}

\frac{\frac{π}{6}}{2} = \frac{π}{12}

\frac{\frac{π}{6}}{2}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{π}{6 \cdot 2}

数字相乘:

6 \cdot 2 = 12

= \frac{π}{12}

= \frac{π}{12} + \frac{πn}{2}

x = \frac{π}{12} + \frac{πn}{2}

x = \frac{π}{12} + \frac{πn}{2}

x = \frac{π}{12} + \frac{πn}{2}

x = \frac{π}{12} + \frac{πn}{2}

作图

流行的例子

sin^2(θ)=5(cos(θ)+1)

sin^{2} (θ) = 5 (cos (θ) + 1)

2cos^2(x)+3sin(x)-3=0

2 cos^{2} (x) + 3 sin (x) - 3 = 0

cos^2(x)=sin^2(x)

cos^{2} (x) = sin^{2} (x)

sin(x+pi/4)+sin(x-pi/4)=-1

sin (x + \frac{π}{4}) + sin (x - \frac{π}{4}) = - 1

cos (\frac{x}{4}) = 0