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人気のある三角関数 >

(2(19.4)sin(45))/(9.8)

解

\frac{2 ( 19.4 ) sin ( 4 5 ^{\circ} )}{9.8}

解

\frac{97 2}{49}

+1

十進法表記

2.79956 \dots

解答ステップ

\frac{2 ( 19.4 ) sin ( 4 5 ^{\circ} )}{9.8}

= \frac{2 \cdot \frac{97}{5} sin ( 4 5 ^{\circ} )}{\frac{49}{5}}

次の自明恒等式を使用する:

sin (4 5^{\circ}) = \frac{2}{2}

sin (4 5^{\circ})

sin (x)

36 0^{\circ} n

循環を含む周期性テーブル:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{2}{2}

= \frac{2 \cdot \frac{97}{5} \cdot \frac{2}{2}}{\frac{49}{5}}

簡素化

\frac{2 \cdot \frac{97}{5} \cdot \frac{2}{2}}{\frac{49}{5}} : \frac{97 2}{49}

\frac{2 \cdot \frac{97}{5} \cdot \frac{2}{2}}{\frac{49}{5}}

分数の規則を適用する:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{2 \cdot \frac{97}{5} \cdot \frac{2}{2} \cdot 5}{49}

数を乗じる:

2 \cdot 5 = 10

= \frac{10 \cdot \frac{97}{5} \cdot \frac{2}{2}}{49}

乗じる

10 \cdot \frac{97}{5} \cdot \frac{2}{2} : 972

10 \cdot \frac{97}{5} \cdot \frac{2}{2}

分数を乗じる:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{97 2 \cdot 10}{5 \cdot 2}

数を乗じる:

97 \cdot 10 = 970

= \frac{970 2}{5 \cdot 2}

数を乗じる:

5 \cdot 2 = 10

= \frac{970 2}{10}

数を割る:

\frac{970}{10} = 97

= 972

= \frac{97 2}{49}

= \frac{97 2}{49}

人気の例

7 sin (16 0^{\circ})

sec((7pi)/(12))

sec (\frac{7 π}{12})

10 \cdot cos (3 7^{\circ})

cos((23pi)/(24))sin((17pi)/(24))

cos (\frac{23 π}{24}) sin (\frac{17 π}{24})

sin(2arccos(1/5))

sin (2 arccos (\frac{1}{5}))