What is the value of -tan(-pi/3) ?

The value of -tan(-pi/3) is square root of 3

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-tan(-pi/3)

- tan (- \frac{π}{3})

3

Decimal Notation

1.73205 \dots

Solution steps

- tan (- \frac{π}{3})

Rewrite using trig identities:

tan (- \frac{π}{3}) = - 3

tan (- \frac{π}{3})

Use the following property:

tan (- x) = - tan (x)

tan (- \frac{π}{3}) = - tan (\frac{π}{3})

= - tan (\frac{π}{3})

Use the following trivial identity:

tan (\frac{π}{3}) = 3

tan (\frac{π}{3})

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

= 3

= - 3

= - (- 3)

Simplify

= 3

1^{s e c (1)}

arccos (cos (- \frac{23 π}{12}))

- arctan (\frac{1}{3})

10 \cdot sin (3 6^{\circ})

arccos (cos (- \frac{19 π}{10}))