What is the value of sin(arccos(1/2)+arctan(1)) ?

The value of sin(arccos(1/2)+arctan(1)) is (sqrt(2)(sqrt(3)+1))/4

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Popular >

sin(arccos(1/2)+arctan(1))

Solution

sin (arccos (\frac{1}{2}) + arctan (1))

Solution

\frac{2 ( 3 + 1 )}{4}

Decimal Notation

0.96592 \dots

Solution steps

sin (arccos (\frac{1}{2}) + arctan (1))

Rewrite using trig identities:

sin (arccos (\frac{1}{2})) cos (arctan (1)) + cos (arccos (\frac{1}{2})) sin (arctan (1))

sin (arccos (\frac{1}{2}) + arctan (1))

Use the Angle Sum identity:

sin (s + t) = sin (s) cos (t) + cos (s) sin (t)

= sin (arccos (\frac{1}{2})) cos (arctan (1)) + cos (arccos (\frac{1}{2})) sin (arctan (1))

= sin (arccos (\frac{1}{2})) cos (arctan (1)) + cos (arccos (\frac{1}{2})) sin (arctan (1))

Rewrite using trig identities:

sin (arccos (\frac{1}{2})) = \frac{3}{2}

sin (arccos (\frac{1}{2}))

Rewrite using trig identities:

sin (arccos (\frac{1}{2})) = 1 - (\frac{1}{2})^{2}

Use the following identity:

sin (arccos (x)) = 1 - x^{2}

= 1 - (\frac{1}{2})^{2}

= 1 - (\frac{1}{2})^{2}

Simplify

= \frac{3}{2}

Rewrite using trig identities:

cos (arctan (1)) = \frac{2}{2}

cos (arctan (1))

Rewrite using trig identities:

cos (arctan (1)) = \frac{1 + 1 ^{2}}{1 + 1 ^{2}}

Use the following identity:

cos (arctan (x)) = \frac{1 + x ^{2}}{1 + x ^{2}}

= \frac{1 + 1 ^{2}}{1 + 1 ^{2}}

= \frac{1 + 1 ^{2}}{1 + 1 ^{2}}

Simplify

= \frac{2}{2}

Rewrite using trig identities:

cos (arccos (\frac{1}{2})) = \frac{1}{2}

Use the following identity:

cos (arccos (x)) = x

= \frac{1}{2}

Rewrite using trig identities:

sin (arctan (1)) = \frac{2}{2}

sin (arctan (1))

Rewrite using trig identities:

sin (arctan (1)) = \frac{1 \cdot 1 + 1 ^{2}}{1 + 1 ^{2}}

Use the following identity:

sin (arctan (x)) = \frac{x 1 + x ^{2}}{1 + x ^{2}}

= \frac{1 \cdot 1 + 1 ^{2}}{1 + 1 ^{2}}

= \frac{1 \cdot 1 + 1 ^{2}}{1 + 1 ^{2}}

Simplify

= \frac{2}{2}

= \frac{3}{2} \cdot \frac{2}{2} + \frac{1}{2} \cdot \frac{2}{2}

Simplify

\frac{3}{2} \cdot \frac{2}{2} + \frac{1}{2} \cdot \frac{2}{2} : \frac{2 ( 3 + 1 )}{4}

\frac{3}{2} \cdot \frac{2}{2} + \frac{1}{2} \cdot \frac{2}{2}

Factor out common term

\frac{2}{2}

= \frac{2}{2} (\frac{3}{2} + \frac{1}{2})

\frac{3}{2} + \frac{1}{2} = \frac{3 + 1}{2}

\frac{3}{2} + \frac{1}{2}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{3 + 1}{2}

= \frac{2}{2} \cdot \frac{1 + 3}{2}

Multiply fractions:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( 3 + 1 ) 2}{2 \cdot 2}

Multiply the numbers:

2 \cdot 2 = 4

= \frac{2 ( 1 + 3 )}{4}

= \frac{2 ( 3 + 1 )}{4}

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Frequently Asked Questions (FAQ)

What is the value of sin(arccos(1/2)+arctan(1)) ?
The value of sin(arccos(1/2)+arctan(1)) is (sqrt(2)(sqrt(3)+1))/4