What is the value of sin(0+pi/2) ?

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sin(0+pi/2)

sin (0 + \frac{π}{2})

1

Solution steps

sin (0 + \frac{π}{2})

Simplify

= sin (\frac{π}{2})

Use the following trivial identity:

sin (\frac{π}{2}) = 1

sin (\frac{π}{2})

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 1

= 1

10 cos (5 0^{\circ})

arctan (1.79)

cos (\frac{3 π}{2}) cos (π) - sin (\frac{3 π}{2}) sin (π)

\frac{2 - 2 + 2 cos ( 8 0 ^{\circ} )}{sin ( 4 0 ^{\circ} )}

\frac{4}{sin ( 3 5 ^{\circ} )}