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Popular Trigonometry >

coth(ln(5))

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Solution

coth(ln(5))

Solution

1213​
+1
Decimal
1.08333…
Solution steps
coth(ln(5))
Use the Hyperbolic identity: coth(x)=ex−e−xex+e−x​=eln(5)−e−ln(5)eln(5)+e−ln(5)​
eln(5)−e−ln(5)eln(5)+e−ln(5)​=1213​
eln(5)−e−ln(5)eln(5)+e−ln(5)​
eln(5)=5
eln(5)
Apply log rule: aloga​(b)=b=5
e−ln(5)=5−1
e−ln(5)
Apply exponent rule: abc=(ab)c=(eln(5))−1
Apply log rule: aloga​(b)=beln(5)=5=5−1
=5−5−1eln(5)+e−ln(5)​
eln(5)=5
eln(5)
Apply log rule: aloga​(b)=b=5
e−ln(5)=5−1
e−ln(5)
Apply exponent rule: abc=(ab)c=(eln(5))−1
Apply log rule: aloga​(b)=beln(5)=5=5−1
=5−5−15+5−1​
Simplify
5−5−15+5−1​
Apply exponent rule: a−1=a1​5−1=51​=5−51​5+5−1​
Apply exponent rule: a−1=a1​5−1=51​=5−51​5+51​​
Join 5−51​:524​
5−51​
Convert element to fraction: 5=55⋅5​=55⋅5​−51​
Since the denominators are equal, combine the fractions: ca​±cb​=ca±b​=55⋅5−1​
5⋅5−1=24
5⋅5−1
Multiply the numbers: 5⋅5=25=25−1
Subtract the numbers: 25−1=24=24
=524​
=524​5+51​​
Join 5+51​:526​
5+51​
Convert element to fraction: 5=55⋅5​=55⋅5​+51​
Since the denominators are equal, combine the fractions: ca​±cb​=ca±b​=55⋅5+1​
5⋅5+1=26
5⋅5+1
Multiply the numbers: 5⋅5=25=25+1
Add the numbers: 25+1=26=26
=526​
=524​526​​
Divide fractions: dc​ba​​=b⋅ca⋅d​=5⋅2426⋅5​
Cancel the common factor: 5=2426​
Cancel the common factor: 2=1213​
=1213​
=1213​

Popular Examples

coth(ln(2))arcsin(1.4)9.81sin(30)120*cos(30)tan^2(45-28/2)

Frequently Asked Questions (FAQ)

  • What is the value of coth(ln(5)) ?

    The value of coth(ln(5)) is 13/12
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