{
"query": {
"display": "10 nPr 6",
"symbolab_question": "#10 nPr 6"
},
"solution": {
"level": "PERFORMED",
"subject": "Statistics",
"topic": "nCr",
"subTopic": "Other",
"default": "151200"
},
"steps": {
"type": "interim",
"title": "$$10\\:nPr\\:6:{\\quad}151200$$",
"steps": [
{
"type": "definition",
"title": "n choose r",
"text": "The number of possibilities for choosing an ordered set of r objects from a total of n objects<br/>$$nPr=\\frac{n!}{\\left(n-r\\right)!}$$"
},
{
"type": "step",
"result": "=\\frac{n!}{\\left(n-r\\right)!}"
},
{
"type": "step",
"primary": "Plug in $$n=10,\\:r=6$$",
"result": "=\\frac{10!}{\\left(10-6\\right)!}"
},
{
"type": "interim",
"title": "$$\\frac{10!}{\\left(10-6\\right)!}=151200$$",
"input": "\\frac{10!}{\\left(10-6\\right)!}",
"result": "=151200",
"steps": [
{
"type": "step",
"primary": "Subtract the numbers: $$10-6=4$$",
"result": "=\\frac{10!}{4!}"
},
{
"type": "step",
"primary": "Cancel the factorials: $$\\frac{n!}{\\left(n-m\\right)!}=n\\cdot\\left(n-1\\right)\\cdots\\left(n-m+1\\right),\\:n>m$$",
"secondary": [
"$$\\frac{10!}{4!}=10\\cdot\\:9\\cdot\\:8\\cdot\\:7\\cdot\\:6\\cdot\\:5$$"
],
"result": "=10\\cdot\\:9\\cdot\\:8\\cdot\\:7\\cdot\\:6\\cdot\\:5"
},
{
"type": "step",
"primary": "Refine",
"result": "=151200"
}
],
"meta": {
"solvingClass": "Solver"
}
}
]
}
}
Solution
10 nPr 6
Solution
Solution steps
Plug in
Popular Examples
variance of-25,2,3,3,8,10,12,14,18,21,21variance 18 choose 2arithmeticmean of 6,7,8,9,10average std of 3,4,5,7,7,7,9standard deviation mode of 90,97,95,93,90mode
Frequently Asked Questions (FAQ)
What is 10 nPr 6 ?
The answer to 10 nPr 6 is 151200