{
"query": {
"display": "upper quartile $$9.4,\\:48.4,\\:35.4,\\:37,\\:29,\\:31,\\:64.4,\\:37.4,\\:16.6,\\:28.6$$",
"symbolab_question": "STATISTICS#thirdquartile 9.4,48.4,35.4,37,29,31,64.4,37.4,16.6,28.6"
},
"solution": {
"level": "PERFORMED",
"subject": "Statistics",
"topic": "thirdquartile",
"subTopic": "Other",
"default": "37.4"
},
"steps": {
"type": "interim",
"title": "Third Quartile (upper quartile) of $$9.4,\\:48.4,\\:35.4,\\:37,\\:29,\\:31,\\:64.4,\\:37.4,\\:16.6,\\:28.6:{\\quad}37.4$$",
"steps": [
{
"type": "definition",
"title": "Third Quartile",
"text": "The third quartile is the value separating the lower three-quarters and higher quarters of the data set.<br/>The third quartile is computed by taking the median of the higher half of a sorted set."
},
{
"type": "step",
"primary": "Arrange the terms in ascending order",
"result": "9.4,\\:16.6,\\:28.6,\\:29,\\:31,\\:35.4,\\:37,\\:37.4,\\:48.4,\\:64.4"
},
{
"type": "interim",
"title": "Take the upper half of the ascending set:$${\\quad}35.4,\\:37,\\:37.4,\\:48.4,\\:64.4$$",
"steps": [
{
"type": "step",
"primary": "Count the number of terms in the data set",
"result": "\\begin{Bmatrix}9.4&16.6&28.6&29&31&35.4&37&37.4&48.4&64.4\\\\1&2&3&4&5&6&7&8&9&10\\end{Bmatrix}"
},
{
"type": "step",
"primary": "The number of terms in the data set is",
"result": "10"
},
{
"type": "step",
"primary": "Take the upper $$5$$ terms",
"result": "35.4,\\:37,\\:37.4,\\:48.4,\\:64.4"
}
],
"meta": {
"interimType": "Take The Upper Half Specific 0Eq"
}
},
{
"type": "interim",
"title": "Median of $$35.4,\\:37,\\:37.4,\\:48.4,\\:64.4:{\\quad}37.4$$",
"steps": [
{
"type": "definition",
"title": "Median",
"text": "The median is the value separating the higher half of the data set, from the lower half.<br/>If the number of terms is odd, then the median is the middle element of the sorted set<br/>If the number of terms is even, then the median is the arithmetic mean of the two middle elements of the sorted set"
},
{
"type": "step",
"primary": "Arrange the terms in ascending order",
"result": "35.4,\\:37,\\:37.4,\\:48.4,\\:64.4"
},
{
"type": "interim",
"title": "Find the median of the ascending set:$${\\quad}37.4$$",
"steps": [
{
"type": "step",
"primary": "Count the number of terms in the data set",
"result": "\\begin{Bmatrix}35.4&37&37.4&48.4&64.4\\\\1&2&3&4&5\\end{Bmatrix}"
},
{
"type": "step",
"primary": "The number of terms in the data set is",
"result": "5"
},
{
"type": "step",
"primary": "Since the number of terms is odd, the median is the middle element of the sorted set.",
"result": "37.4"
}
],
"meta": {
"interimType": "Get Median From Ascending List 0Eq"
}
},
{
"type": "step",
"result": "37.4"
}
],
"meta": {
"interimType": "Median Top 1Eq"
}
},
{
"type": "step",
"result": "37.4"
}
]
}
}
Solution
upper quartile
Solution
Solution steps
Arrange the terms in ascending order
Take the upper half of the ascending set:
Median of
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Frequently Asked Questions (FAQ)
What is the thirdquartile 9.4,48.4,35.4,37,29,31,64.4,37.4,16.6,28.6 ?
The thirdquartile 9.4,48.4,35.4,37,29,31,64.4,37.4,16.6,28.6 is 37.4