What is the derivative of y=sqrt(x) ?

The derivative of y=sqrt(x) is 1/(2sqrt(x))

What is the first derivative of y=sqrt(x) ?

The first derivative of y=sqrt(x) is 1/(2sqrt(x))

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derivative of

y = x

\frac{1}{2 x}

Solution steps

\frac{d}{d x} (x)

Apply radical rule:

a = a^{\frac{1}{2}}

= \frac{d}{d x} (x^{\frac{1}{2}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{2} x^{\frac{1}{2} - 1}

Simplify

\frac{1}{2} x^{\frac{1}{2} - 1} : \frac{1}{2 x}

= \frac{1}{2 x}

(4, \frac{3 π}{2})

x^{2} + y^{2} - 4 x = 0

4 y = 5 x - 8

(0, - 2)

(0, 2)

What is the derivative of y=sqrt(x) ?
The derivative of y=sqrt(x) is 1/(2sqrt(x))
What is the first derivative of y=sqrt(x) ?
The first derivative of y=sqrt(x) is 1/(2sqrt(x))