{
"query": {
"display": "derivative of $$f\\left(x\\right)=\\left(2\\sin^{3}\\left(x\\right)-5x\\right)^{\\frac{5}{3}}$$",
"symbolab_question": "PRE_CALC#derivative f(x)=(2\\sin^{3}(x)-5x)^{\\frac{5}{3}}"
},
"solution": {
"level": "PERFORMED",
"subject": "Calculus",
"topic": "Derivatives",
"subTopic": "Derivatives",
"default": "\\frac{5(6\\sin^{2}(x)\\cos(x)-5)(2\\sin^{3}(x)-5x)^{\\frac{2}{3}}}{3}",
"meta": {
"showVerify": true
}
},
"steps": {
"type": "interim",
"title": "$$\\frac{d}{dx}\\left(\\left(2\\sin^{3}\\left(x\\right)-5x\\right)^{\\frac{5}{3}}\\right)=\\frac{5\\left(6\\sin^{2}\\left(x\\right)\\cos\\left(x\\right)-5\\right)\\left(2\\sin^{3}\\left(x\\right)-5x\\right)^{\\frac{2}{3}}}{3}$$",
"input": "\\frac{d}{dx}\\left(\\left(2\\sin^{3}\\left(x\\right)-5x\\right)^{\\frac{5}{3}}\\right)",
"steps": [
{
"type": "interim",
"title": "Apply the chain rule:$${\\quad}\\frac{5\\left(2\\sin^{3}\\left(x\\right)-5x\\right)^{\\frac{2}{3}}}{3}\\frac{d}{dx}\\left(2\\sin^{3}\\left(x\\right)-5x\\right)$$",
"input": "\\frac{d}{dx}\\left(\\left(2\\sin^{3}\\left(x\\right)-5x\\right)^{\\frac{5}{3}}\\right)",
"result": "=\\frac{5\\left(2\\sin^{3}\\left(x\\right)-5x\\right)^{\\frac{2}{3}}}{3}\\frac{d}{dx}\\left(2\\sin^{3}\\left(x\\right)-5x\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the chain rule: $$\\frac{df\\left(u\\right)}{dx}=\\frac{df}{du}\\cdot\\frac{du}{dx}$$",
"secondary": [
"$$f=u^{\\frac{5}{3}},\\:\\:u=\\left(2\\sin^{3}\\left(x\\right)-5x\\right)$$"
],
"result": "=\\frac{d}{du}\\left(u^{\\frac{5}{3}}\\right)\\frac{d}{dx}\\left(\\left(2\\sin^{3}\\left(x\\right)-5x\\right)\\right)",
"meta": {
"practiceLink": "/practice/derivatives-practice#area=main&subtopic=Chain%20Rule",
"practiceTopic": "Chain Rule"
}
},
{
"type": "interim",
"title": "$$\\frac{d}{du}\\left(u^{\\frac{5}{3}}\\right)=\\frac{5u^{\\frac{2}{3}}}{3}$$",
"input": "\\frac{d}{du}\\left(u^{\\frac{5}{3}}\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the Power Rule: $$\\frac{d}{dx}\\left(x^a\\right)=a{\\cdot}x^{a-1}$$",
"result": "=\\frac{5}{3}u^{\\frac{5}{3}-1}",
"meta": {
"practiceLink": "/practice/derivatives-practice#area=main&subtopic=Power%20Rule",
"practiceTopic": "Power Rule"
}
},
{
"type": "interim",
"title": "Simplify $$\\frac{5}{3}u^{\\frac{5}{3}-1}:{\\quad}\\frac{5u^{\\frac{2}{3}}}{3}$$",
"input": "\\frac{5}{3}u^{\\frac{5}{3}-1}",
"result": "=\\frac{5u^{\\frac{2}{3}}}{3}",
"steps": [
{
"type": "interim",
"title": "$$u^{\\frac{5}{3}-1}=u^{\\frac{2}{3}}$$",
"input": "u^{\\frac{5}{3}-1}",
"steps": [
{
"type": "interim",
"title": "Join $$\\frac{5}{3}-1:{\\quad}\\frac{2}{3}$$",
"input": "\\frac{5}{3}-1",
"result": "=u^{\\frac{2}{3}}",
"steps": [
{
"type": "step",
"primary": "Convert element to fraction: $$1=\\frac{1\\cdot\\:3}{3}$$",
"result": "=-\\frac{1\\cdot\\:3}{3}+\\frac{5}{3}"
},
{
"type": "step",
"primary": "Since the denominators are equal, combine the fractions: $$\\frac{a}{c}\\pm\\frac{b}{c}=\\frac{a\\pm\\:b}{c}$$",
"result": "=\\frac{-1\\cdot\\:3+5}{3}"
},
{
"type": "interim",
"title": "$$-1\\cdot\\:3+5=2$$",
"input": "-1\\cdot\\:3+5",
"steps": [
{
"type": "step",
"primary": "Multiply the numbers: $$1\\cdot\\:3=3$$",
"result": "=-3+5"
},
{
"type": "step",
"primary": "Add/Subtract the numbers: $$-3+5=2$$",
"result": "=2"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
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}
},
{
"type": "step",
"result": "=\\frac{2}{3}"
}
],
"meta": {
"interimType": "Algebraic Manipulation Join Concise Title 1Eq"
}
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7pdTyORg72Xwp/fTU7gw1m+0se7vRyav6BwUCJZptwG3MwViaLUXkeD+JukROhWdjrAnm+0dWV2G5ts+qDasw1P8//6/nV5O4fb8Xgwi7marpZlpPA1sHTvP5viOtpjQ/MMgFYo0k1nCcObJSAQu6gs67uJicgMpLzW5Yu+HQ/jQ="
}
},
{
"type": "step",
"result": "=\\frac{5}{3}u^{\\frac{2}{3}}"
},
{
"type": "step",
"primary": "Multiply fractions: $$a\\cdot\\frac{b}{c}=\\frac{a\\:\\cdot\\:b}{c}$$",
"result": "=\\frac{5u^{\\frac{2}{3}}}{3}"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Generic Simplify Specific 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7HEcdymjQozFmRk5Oh5FBzbCttvJlYc8bs4y+5RPcRqgAlilG71elit3w1IBbYN0P8rEus7TgCihQBF5omOFkJgwOKsVAiPOfX+lJC9WiIMvDakV5xtzrC6sUYTlsYKLn1sD7NfhsPe7eDHrmjY0mE8DwQcN28geUT7aUsumC7doBDKD2XvEYcwnHxnLYU/iA2sn2RC+c/BDkqFyxK4HceQ=="
}
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives"
}
},
{
"type": "step",
"result": "=\\frac{5u^{\\frac{2}{3}}}{3}\\frac{d}{dx}\\left(\\left(2\\sin^{3}\\left(x\\right)-5x\\right)\\right)"
},
{
"type": "step",
"primary": "Substitute back $$u=\\left(2\\sin^{3}\\left(x\\right)-5x\\right)$$",
"result": "=\\frac{5\\left(2\\sin^{3}\\left(x\\right)-5x\\right)^{\\frac{2}{3}}}{3}\\frac{d}{dx}\\left(2\\sin^{3}\\left(x\\right)-5x\\right)"
}
],
"meta": {
"interimType": "Derivative Chain Rule 0Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYsKTtXGfF/MkSl78WXXxyvUjNNt59C2HWoB/JNL4KKqbC7vGbZ2u0RQZ8l5TbOwGxgeNnQmZ4ALdlISYzFZE1i7peVGypUVICZb3mm1LEudSIBz+GKlpIeTjh2kq0P5fEfH0HO6o5Ykj5thooWcS37OimxKlJxew+85S9cHc2ICABh7Z+NaTHtThPA34waXeGfnVNlUlUrdnxP5m4O9D1TyD63WlyOmbnHNz6QflRNyR8LfSxJ+0AgVLpCSnLX0iSs2zS5GGbCZa1X3a2T5z/xm7+YNMdwDOICJh407OOWgm"
}
},
{
"type": "interim",
"title": "$$\\frac{d}{dx}\\left(2\\sin^{3}\\left(x\\right)-5x\\right)=6\\sin^{2}\\left(x\\right)\\cos\\left(x\\right)-5$$",
"input": "\\frac{d}{dx}\\left(2\\sin^{3}\\left(x\\right)-5x\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the Sum/Difference Rule: $$\\left(f{\\pm}g\\right)'=f'{\\pm}g'$$",
"result": "=\\frac{d}{dx}\\left(2\\sin^{3}\\left(x\\right)\\right)-\\frac{d}{dx}\\left(5x\\right)"
},
{
"type": "interim",
"title": "$$\\frac{d}{dx}\\left(2\\sin^{3}\\left(x\\right)\\right)=6\\sin^{2}\\left(x\\right)\\cos\\left(x\\right)$$",
"input": "\\frac{d}{dx}\\left(2\\sin^{3}\\left(x\\right)\\right)",
"steps": [
{
"type": "step",
"primary": "Take the constant out: $$\\left(a{\\cdot}f\\right)'=a{\\cdot}f'$$",
"result": "=2\\frac{d}{dx}\\left(\\sin^{3}\\left(x\\right)\\right)"
},
{
"type": "interim",
"title": "Apply the chain rule:$${\\quad}3\\left(\\sin\\left(x\\right)\\right)^{2}\\frac{d}{dx}\\left(\\sin\\left(x\\right)\\right)$$",
"input": "\\frac{d}{dx}\\left(\\sin^{3}\\left(x\\right)\\right)",
"result": "=3\\left(\\sin\\left(x\\right)\\right)^{2}\\frac{d}{dx}\\left(\\sin\\left(x\\right)\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the chain rule: $$\\frac{df\\left(u\\right)}{dx}=\\frac{df}{du}\\cdot\\frac{du}{dx}$$",
"secondary": [
"$$f=u^{3},\\:\\:u=\\sin\\left(x\\right)$$"
],
"result": "=\\frac{d}{du}\\left(u^{3}\\right)\\frac{d}{dx}\\left(\\sin\\left(x\\right)\\right)",
"meta": {
"practiceLink": "/practice/derivatives-practice#area=main&subtopic=Chain%20Rule",
"practiceTopic": "Chain Rule"
}
},
{
"type": "interim",
"title": "$$\\frac{d}{du}\\left(u^{3}\\right)=3u^{2}$$",
"input": "\\frac{d}{du}\\left(u^{3}\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the Power Rule: $$\\frac{d}{dx}\\left(x^a\\right)=a{\\cdot}x^{a-1}$$",
"result": "=3u^{3-1}",
"meta": {
"practiceLink": "/practice/derivatives-practice#area=main&subtopic=Power%20Rule",
"practiceTopic": "Power Rule"
}
},
{
"type": "step",
"primary": "Simplify",
"result": "=3u^{2}",
"meta": {
"solvingClass": "Solver"
}
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYjNrXZy15fg+DDm4IZ/kmJKk3hxk9aCfAWodBRxXgUexYrhQEWwJJMG//0JI2CMZRv8//6/nV5O4fb8Xgwi7mapNFxUvwBeni+JEIFAdbegz8nAGF3XMCO2i5cp0uYL6iA=="
}
},
{
"type": "step",
"result": "=3u^{2}\\frac{d}{dx}\\left(\\sin\\left(x\\right)\\right)"
},
{
"type": "step",
"primary": "Substitute back $$u=\\sin\\left(x\\right)$$",
"result": "=3\\left(\\sin\\left(x\\right)\\right)^{2}\\frac{d}{dx}\\left(\\sin\\left(x\\right)\\right)"
}
],
"meta": {
"interimType": "Derivative Chain Rule 0Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYqNxjWGE58H9oI7CDLL2A/4Xi79ycACn3XhxThCpcRNo1NpEj4yUFTERoeqJRRLYHBPiZ+52xB2X1cQ6EdG5IQO8Lf1Cr1RIMG05OFJAphwe/anAJHqrRTzOIpfDjrc9tHVYsbkCD4DRWIECF2dTStlkS3dlcCKpQTQcheuut7MkqkSK49J17AMxV6yOujf/eqTH+HXrxKfWuw8Vmw3VWoA="
}
},
{
"type": "interim",
"title": "$$\\frac{d}{dx}\\left(\\sin\\left(x\\right)\\right)=\\cos\\left(x\\right)$$",
"input": "\\frac{d}{dx}\\left(\\sin\\left(x\\right)\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the common derivative: $$\\frac{d}{dx}\\left(\\sin\\left(x\\right)\\right)=\\cos\\left(x\\right)$$",
"result": "=\\cos\\left(x\\right)"
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYgOt2FhQQwx0GxLGzv2mPOv8zeERICEnv1Ds5A1/BdIwQslTDKxOR/6J+ZOGvUcaugB66mSUqneplfTkjggryzA+YUX37Aa/AAEf1Hkty8FUj7LPbFLewMJWlj8VtjhXr5J/4xg9Nn6C/zrAXreziPc="
}
},
{
"type": "step",
"result": "=2\\cdot\\:3\\left(\\sin\\left(x\\right)\\right)^{2}\\cos\\left(x\\right)"
},
{
"type": "step",
"primary": "Simplify",
"result": "=6\\sin^{2}\\left(x\\right)\\cos\\left(x\\right)",
"meta": {
"solvingClass": "Solver"
}
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives"
}
},
{
"type": "interim",
"title": "$$\\frac{d}{dx}\\left(5x\\right)=5$$",
"input": "\\frac{d}{dx}\\left(5x\\right)",
"steps": [
{
"type": "step",
"primary": "Take the constant out: $$\\left(a{\\cdot}f\\right)'=a{\\cdot}f'$$",
"result": "=5\\frac{dx}{dx}"
},
{
"type": "step",
"primary": "Apply the common derivative: $$\\frac{dx}{dx}=1$$",
"result": "=5\\cdot\\:1"
},
{
"type": "step",
"primary": "Simplify",
"result": "=5",
"meta": {
"solvingClass": "Solver"
}
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYmZ9X+BZ/JyYYY1hJF6v/r/ZGku9zFkxwe1dTH8vycb9dZwuGwx+eQcEBv+dY3CjTFNbbqpyK7JQEZdATEJR51hJPYdcyzxncaY/pkYJ4XZq"
}
},
{
"type": "step",
"result": "=6\\sin^{2}\\left(x\\right)\\cos\\left(x\\right)-5"
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives"
}
},
{
"type": "step",
"result": "=\\frac{5\\left(2\\sin^{3}\\left(x\\right)-5x\\right)^{\\frac{2}{3}}}{3}\\left(6\\sin^{2}\\left(x\\right)\\cos\\left(x\\right)-5\\right)"
},
{
"type": "step",
"primary": "Multiply fractions: $$a\\cdot\\frac{b}{c}=\\frac{a\\:\\cdot\\:b}{c}$$",
"result": "=\\frac{5\\left(6\\sin^{2}\\left(x\\right)\\cos\\left(x\\right)-5\\right)\\left(2\\sin^{3}\\left(x\\right)-5x\\right)^{\\frac{2}{3}}}{3}",
"meta": {
"solvingClass": "Solver"
}
}
],
"meta": {
"solvingClass": "Derivatives",
"practiceLink": "/practice/derivatives-practice",
"practiceTopic": "Derivatives"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "x",
"plotRequest": "y=\\frac{5(6\\sin^{2}(x)\\cos(x)-5)(2\\sin^{3}(x)-5x)^{\\frac{2}{3}}}{3}"
},
"showViewLarger": true
}
},
"meta": {
"showVerify": true
}
}
Solution
derivative of
Solution
Solution steps
Apply the chain rule:
Multiply fractions:
Graph
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Frequently Asked Questions (FAQ)
What is the derivative of f(x)=(2sin^3(x)-5x)^{5/3} ?
The derivative of f(x)=(2sin^3(x)-5x)^{5/3} is (5(6sin^2(x)cos(x)-5)(2sin^3(x)-5x)^{2/3})/3What is the first derivative of f(x)=(2sin^3(x)-5x)^{5/3} ?
The first derivative of f(x)=(2sin^3(x)-5x)^{5/3} is (5(6sin^2(x)cos(x)-5)(2sin^3(x)-5x)^{2/3})/3