What is the first derivative of 3x^2 ?

The first derivative of 3x^2 is 6x

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derivative of 3x^2

derivative of

3 x^{2}

6 x

Solution steps

\frac{d}{d x} (3 x^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 \cdot 2 x^{2 - 1}

Simplify

= 6 x

f (x) = x, at x = 4

ln (2 x - 1) - ln (x - 1)

f (x) = sin (2 x)

y = 3 x + 5

y = \frac{x ^{2}}{x - 1}, (0, 0)