What is the tangent of f(x)=x^2+6x+1,\at x=-2 ?

The tangent of f(x)=x^2+6x+1,\at x=-2 is y=2x-3

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tangent of f(x)=x^2+6x+1,\at x=-2

tangent

y = 2 x - 3

Solution steps

Find the tangent point:

(- 2, - 7)

Find the slope of

f (x) = x^{2} + 6 x + 1 : \frac{df ( x )}{d x} = 2 x + 6

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 2

Find the line with slope m=

2

and passing through

(- 2, - 7) : y = 2 x - 3

y = 2 x - 3

What is the tangent of f(x)=x^2+6x+1,\at x=-2 ?
The tangent of f(x)=x^2+6x+1,\at x=-2 is y=2x-3