What is the derivative of f(x)=2x^2-3x ?

The derivative of f(x)=2x^2-3x is 4x-3

What is the first derivative of f(x)=2x^2-3x ?

The first derivative of f(x)=2x^2-3x is 4x-3

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derivative of

f (x) = 2 x^{2} - 3 x

4 x - 3

Solution steps

\frac{d}{d x} (2 x^{2} - 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (3 x)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (3 x) = 3

= 4 x - 3

f (x) = x e^{- x}

5

f (x) = x^{2}

(7, - 5), (9, - 1)

f (x) = 5

What is the derivative of f(x)=2x^2-3x ?
The derivative of f(x)=2x^2-3x is 4x-3
What is the first derivative of f(x)=2x^2-3x ?
The first derivative of f(x)=2x^2-3x is 4x-3