What is the tangent of y=x^2-3x-10,\at x=5.5 ?

The tangent of y=x^2-3x-10,\at x=5.5 is y=8x-40.25

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tangent of y=x^2-3x-10,\at x=5.5

tangent

y = 8 x - 40.25

Solution steps

Find the tangent point:

(5.5, 3.75)

Find the slope of

y = x^{2} - 3 x - 10 : \frac{d y}{d x} = 2 x - 3

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 8

Find the line with slope m=

8

and passing through

(5.5, 3.75) : y = 8 x - 40.25

y = 8 x - 40.25

What is the tangent of y=x^2-3x-10,\at x=5.5 ?
The tangent of y=x^2-3x-10,\at x=5.5 is y=8x-40.25