What is the derivative of f(x)=x^3-x-2 ?

The derivative of f(x)=x^3-x-2 is 3x^2-1

What is the first derivative of f(x)=x^3-x-2 ?

The first derivative of f(x)=x^3-x-2 is 3x^2-1

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derivative of

f (x) = x^{3} - x - 2

3 x^{2} - 1

Solution steps

\frac{d}{d x} (x^{3} - x - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d x}{d x} - \frac{d}{d x} (2)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d x}{d x} = 1

\frac{d}{d x} (2) = 0

= 3 x^{2} - 1 - 0

Simplify

= 3 x^{2} - 1

5 x - y = 4, (2, 0)

(- 1.4) (3.2)

(- \frac{7}{3}, \frac{3}{4}), (\frac{5}{3}, - \frac{9}{4})

r = 4

2 e^{x}

What is the derivative of f(x)=x^3-x-2 ?
The derivative of f(x)=x^3-x-2 is 3x^2-1
What is the first derivative of f(x)=x^3-x-2 ?
The first derivative of f(x)=x^3-x-2 is 3x^2-1