What is the derivative of f(x)=x^2+x ?

The derivative of f(x)=x^2+x is 2x+1

What is the first derivative of f(x)=x^2+x ?

The first derivative of f(x)=x^2+x is 2x+1

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derivative

2 x + 1

Solution steps

\frac{d}{d x} (x^{2} + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d x}{d x}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d x}{d x} = 1

= 2 x + 1

What is the derivative of f(x)=x^2+x ?
The derivative of f(x)=x^2+x is 2x+1
What is the first derivative of f(x)=x^2+x ?
The first derivative of f(x)=x^2+x is 2x+1