What is the derivative of f(x)=x^2+x ?

The derivative of f(x)=x^2+x is 2x+1

What is the first derivative of f(x)=x^2+x ?

The first derivative of f(x)=x^2+x is 2x+1

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derivative of

f (x) = x^{2} + x

2 x + 1

Solution steps

\frac{d}{d x} (x^{2} + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d x}{d x}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d x}{d x} = 1

= 2 x + 1

x = - 3

y = 8 cos (3 x) - 2 sin (4 x)

- \frac{x}{2}

(5, - 5)

f (x) = (x^{2} - 1)^{2}

What is the derivative of f(x)=x^2+x ?
The derivative of f(x)=x^2+x is 2x+1
What is the first derivative of f(x)=x^2+x ?
The first derivative of f(x)=x^2+x is 2x+1