What is the derivative of f(x)=\sqrt[3]{x^2} ?

The derivative of f(x)=\sqrt[3]{x^2} is (2x)/(3(x^2)^{2/3)}

What is the first derivative of f(x)=\sqrt[3]{x^2} ?

The first derivative of f(x)=\sqrt[3]{x^2} is (2x)/(3(x^2)^{2/3)}

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derivative of

\frac{2 x}{3 ( x ^{2} ) ^{\frac{2}{3}}}

Solution steps

Apply the chain rule:

\frac{1}{3 ( x ^{2} ) ^{\frac{2}{3}}} \frac{d}{d x} (x^{2})

= \frac{1}{3 ( x ^{2} ) ^{\frac{2}{3}}} \frac{d}{d x} (x^{2})

\frac{d}{d x} (x^{2}) = 2 x

= \frac{1}{3 ( x ^{2} ) ^{\frac{2}{3}}} \cdot 2 x

Simplify

\frac{1}{3 ( x ^{2} ) ^{\frac{2}{3}}} \cdot 2 x : \frac{2 x}{3 ( x ^{2} ) ^{\frac{2}{3}}}

= \frac{2 x}{3 ( x ^{2} ) ^{\frac{2}{3}}}

(6, - 6)

x^{2} + y^{2}

f (x) = - \frac{6}{x}, at x = 12

y = cos (2 x)

y = \frac{2}{x ^{2}}

What is the derivative of f(x)=\sqrt[3]{x^2} ?
The derivative of f(x)=\sqrt[3]{x^2} is (2x)/(3(x^2)^{2/3)}
What is the first derivative of f(x)=\sqrt[3]{x^2} ?
The first derivative of f(x)=\sqrt[3]{x^2} is (2x)/(3(x^2)^{2/3)}