What is the derivative of y= 2/x ?

The derivative of y= 2/x is -2/(x^2)

What is the first derivative of y= 2/x ?

The first derivative of y= 2/x is -2/(x^2)

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derivative of

y = \frac{2}{x}

- \frac{2}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{2}{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 (- 1 \cdot x^{- 1 - 1})

Simplify

2 (- 1 \cdot x^{- 1 - 1}) : - \frac{2}{x ^{2}}

= - \frac{2}{x ^{2}}

y = \frac{e ^{x}}{1 - e ^{x}}

5 x - y = 11

x = 2

y = x e^{x}

y = tan (ln (a x + b))

What is the derivative of y= 2/x ?
The derivative of y= 2/x is -2/(x^2)
What is the first derivative of y= 2/x ?
The first derivative of y= 2/x is -2/(x^2)