What is the derivative of x^2-4x+5 ?

The derivative of x^2-4x+5 is 2x-4

What is the first derivative of x^2-4x+5 ?

The first derivative of x^2-4x+5 is 2x-4

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derivative of

x^{2} - 4 x + 5

2 x - 4

Solution steps

\frac{d}{d x} (x^{2} - 4 x + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (4 x) + \frac{d}{d x} (5)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (5) = 0

= 2 x - 4 + 0

Simplify

= 2 x - 4

y = 2 x + 5

x (x - 4)^{3}

f (x) = \frac{1}{x ^{2}}, at x = 2

(- 7, - 7), (- 6, - 1)

(- 4, - 3), (7, - 5)

What is the derivative of x^2-4x+5 ?
The derivative of x^2-4x+5 is 2x-4
What is the first derivative of x^2-4x+5 ?
The first derivative of x^2-4x+5 is 2x-4