What is the derivative of y=x^2-4 ?

The derivative of y=x^2-4 is 2x

What is the first derivative of y=x^2-4 ?

The first derivative of y=x^2-4 is 2x

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derivative of

y = x^{2} - 4

2 x

Solution steps

\frac{d}{d x} (x^{2} - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (4)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4) = 0

= 2 x - 0

Simplify

= 2 x

y - 4 = - 7 (x - 6)

x = 6

1

f (x) = (x + 1)^{2} (x - 4)^{3}

f (x) = x^{\frac{2}{3}}