What is the first derivative of y=2x^2 ?

The first derivative of y=2x^2 is 4x

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derivative of y=2x^2

derivative of

y = 2 x^{2}

4 x

Solution steps

\frac{d}{d x} (2 x^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot 2 x^{2 - 1}

Simplify

= 4 x

x e^{2 x}

f (x) = - 7 x^{\frac{4}{3}} + \frac{4}{x ^{3}}

y^{2} = 4 x

y = 3 x - 5

(0, - 3), (1, - 2)