{
"query": {
"display": "derivative of $$y=\\arcsin\\left(2x+1\\right)$$",
"symbolab_question": "PRE_CALC#derivative y=\\arcsin(2x+1)"
},
"solution": {
"level": "PERFORMED",
"subject": "Calculus",
"topic": "Derivatives",
"subTopic": "Derivatives",
"default": "\\frac{1}{\\sqrt{-x(x+1)}}",
"meta": {
"showVerify": true
}
},
"steps": {
"type": "interim",
"title": "$$\\frac{d}{dx}\\left(\\arcsin\\left(2x+1\\right)\\right)=\\frac{1}{\\sqrt{-x\\left(x+1\\right)}}$$",
"input": "\\frac{d}{dx}\\left(\\arcsin\\left(2x+1\\right)\\right)",
"steps": [
{
"type": "interim",
"title": "Apply the chain rule:$${\\quad}\\frac{1}{\\sqrt{1-\\left(2x+1\\right)^{2}}}\\frac{d}{dx}\\left(2x+1\\right)$$",
"input": "\\frac{d}{dx}\\left(\\arcsin\\left(2x+1\\right)\\right)",
"result": "=\\frac{1}{\\sqrt{1-\\left(2x+1\\right)^{2}}}\\frac{d}{dx}\\left(2x+1\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the chain rule: $$\\frac{df\\left(u\\right)}{dx}=\\frac{df}{du}\\cdot\\frac{du}{dx}$$",
"secondary": [
"$$f=\\arcsin\\left(u\\right),\\:\\:u=2x+1$$"
],
"result": "=\\frac{d}{du}\\left(\\arcsin\\left(u\\right)\\right)\\frac{d}{dx}\\left(2x+1\\right)",
"meta": {
"practiceLink": "/practice/derivatives-practice#area=main&subtopic=Chain%20Rule",
"practiceTopic": "Chain Rule"
}
},
{
"type": "interim",
"title": "$$\\frac{d}{du}\\left(\\arcsin\\left(u\\right)\\right)=\\frac{1}{\\sqrt{1-u^{2}}}$$",
"input": "\\frac{d}{du}\\left(\\arcsin\\left(u\\right)\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the common derivative: $$\\frac{d}{du}\\left(\\arcsin\\left(u\\right)\\right)=\\frac{1}{\\sqrt{1-u^{2}}}$$",
"result": "=\\frac{1}{\\sqrt{1-u^{2}}}"
}
],
"meta": {
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"interimType": "Derivatives",
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}
},
{
"type": "step",
"result": "=\\frac{1}{\\sqrt{1-u^{2}}}\\frac{d}{dx}\\left(2x+1\\right)"
},
{
"type": "step",
"primary": "Substitute back $$u=2x+1$$",
"result": "=\\frac{1}{\\sqrt{1-\\left(2x+1\\right)^{2}}}\\frac{d}{dx}\\left(2x+1\\right)"
}
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},
{
"type": "interim",
"title": "$$\\frac{d}{dx}\\left(2x+1\\right)=2$$",
"input": "\\frac{d}{dx}\\left(2x+1\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the Sum/Difference Rule: $$\\left(f{\\pm}g\\right)'=f'{\\pm}g'$$",
"result": "=\\frac{d}{dx}\\left(2x\\right)+\\frac{d}{dx}\\left(1\\right)"
},
{
"type": "interim",
"title": "$$\\frac{d}{dx}\\left(2x\\right)=2$$",
"input": "\\frac{d}{dx}\\left(2x\\right)",
"steps": [
{
"type": "step",
"primary": "Take the constant out: $$\\left(a{\\cdot}f\\right)'=a{\\cdot}f'$$",
"result": "=2\\frac{dx}{dx}"
},
{
"type": "step",
"primary": "Apply the common derivative: $$\\frac{dx}{dx}=1$$",
"result": "=2\\cdot\\:1"
},
{
"type": "step",
"primary": "Simplify",
"result": "=2",
"meta": {
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"interimType": "Derivatives",
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}
},
{
"type": "interim",
"title": "$$\\frac{d}{dx}\\left(1\\right)=0$$",
"input": "\\frac{d}{dx}\\left(1\\right)",
"steps": [
{
"type": "step",
"primary": "Derivative of a constant: $$\\frac{d}{dx}\\left({a}\\right)=0$$",
"result": "=0"
}
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{
"type": "step",
"result": "=2+0"
},
{
"type": "step",
"primary": "Simplify",
"result": "=2",
"meta": {
"solvingClass": "Solver"
}
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives"
}
},
{
"type": "step",
"result": "=\\frac{1}{\\sqrt{1-\\left(2x+1\\right)^{2}}}\\cdot\\:2"
},
{
"type": "interim",
"title": "Simplify $$\\frac{1}{\\sqrt{1-\\left(2x+1\\right)^{2}}}\\cdot\\:2:{\\quad}\\frac{1}{\\sqrt{-x\\left(x+1\\right)}}$$",
"input": "\\frac{1}{\\sqrt{1-\\left(2x+1\\right)^{2}}}\\cdot\\:2",
"result": "=\\frac{1}{\\sqrt{-x\\left(x+1\\right)}}",
"steps": [
{
"type": "interim",
"title": "$$\\frac{1}{\\sqrt{1-\\left(2x+1\\right)^{2}}}=\\frac{1}{2\\sqrt{-x\\left(x+1\\right)}}$$",
"input": "\\frac{1}{\\sqrt{1-\\left(2x+1\\right)^{2}}}",
"steps": [
{
"type": "interim",
"title": "$$\\sqrt{1-\\left(2x+1\\right)^{2}}=2\\sqrt{-x\\left(x+1\\right)}$$",
"input": "\\sqrt{1-\\left(2x+1\\right)^{2}}",
"steps": [
{
"type": "interim",
"title": "Expand $$1-\\left(2x+1\\right)^{2}:{\\quad}-4x^{2}-4x$$",
"input": "1-\\left(2x+1\\right)^{2}",
"result": "=\\sqrt{-4x^{2}-4x}",
"steps": [
{
"type": "interim",
"title": "$$\\left(2x+1\\right)^{2}:{\\quad}4x^{2}+4x+1$$",
"result": "=1-\\left(4x^{2}+4x+1\\right)",
"steps": [
{
"type": "step",
"primary": "Apply Perfect Square Formula: $$\\left(a+b\\right)^{2}=a^{2}+2ab+b^{2}$$",
"secondary": [
"$$a=2x,\\:\\:b=1$$"
],
"meta": {
"practiceLink": "/practice/expansion-practice#area=main&subtopic=Perfect%20Square",
"practiceTopic": "Expand Perfect Square"
}
},
{
"type": "step",
"result": "=\\left(2x\\right)^{2}+2\\cdot\\:2x\\cdot\\:1+1^{2}"
},
{
"type": "interim",
"title": "Simplify $$\\left(2x\\right)^{2}+2\\cdot\\:2x\\cdot\\:1+1^{2}:{\\quad}4x^{2}+4x+1$$",
"input": "\\left(2x\\right)^{2}+2\\cdot\\:2x\\cdot\\:1+1^{2}",
"result": "=4x^{2}+4x+1",
"steps": [
{
"type": "step",
"primary": "Apply rule $$1^{a}=1$$",
"secondary": [
"$$1^{2}=1$$"
],
"result": "=\\left(2x\\right)^{2}+2\\cdot\\:2\\cdot\\:1\\cdot\\:x+1"
},
{
"type": "interim",
"title": "$$\\left(2x\\right)^{2}=4x^{2}$$",
"input": "\\left(2x\\right)^{2}",
"steps": [
{
"type": "step",
"primary": "Apply exponent rule: $$\\left(a\\cdot\\:b\\right)^{n}=a^{n}b^{n}$$",
"result": "=2^{2}x^{2}",
"meta": {
"practiceLink": "/practice/exponent-practice",
"practiceTopic": "Expand FOIL"
}
},
{
"type": "step",
"primary": "$$2^{2}=4$$",
"result": "=4x^{2}"
}
],
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"interimType": "Solver",
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},
{
"type": "interim",
"title": "$$2\\cdot\\:2x\\cdot\\:1=4x$$",
"input": "2\\cdot\\:2x\\cdot\\:1",
"steps": [
{
"type": "step",
"primary": "Multiply the numbers: $$2\\cdot\\:2\\cdot\\:1=4$$",
"result": "=4x"
}
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},
{
"type": "step",
"result": "=4x^{2}+4x+1"
}
],
"meta": {
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"interimType": "Algebraic Manipulation Simplify Title 1Eq"
}
}
],
"meta": {
"interimType": "N/A"
}
},
{
"type": "interim",
"title": "$$-\\left(4x^{2}+4x+1\\right):{\\quad}-4x^{2}-4x-1$$",
"input": "-\\left(4x^{2}+4x+1\\right)",
"result": "=1-4x^{2}-4x-1",
"steps": [
{
"type": "step",
"primary": "Distribute parentheses",
"result": "=-\\left(4x^{2}\\right)-\\left(4x\\right)-\\left(1\\right)"
},
{
"type": "step",
"primary": "Apply minus-plus rules",
"secondary": [
"$$+\\left(-a\\right)=-a$$"
],
"result": "=-4x^{2}-4x-1"
}
],
"meta": {
"interimType": "N/A"
}
},
{
"type": "interim",
"title": "Simplify $$1-4x^{2}-4x-1:{\\quad}-4x^{2}-4x$$",
"input": "1-4x^{2}-4x-1",
"result": "=-4x^{2}-4x",
"steps": [
{
"type": "step",
"primary": "Group like terms",
"result": "=-4x^{2}-4x+1-1"
},
{
"type": "step",
"primary": "$$1-1=0$$",
"result": "=-4x^{2}-4x"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Algebraic Manipulation Simplify Title 1Eq"
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},
{
"type": "interim",
"title": "Factor $$-4x^{2}-4x:{\\quad}-4x\\left(x+1\\right)$$",
"input": "-4x^{2}-4x",
"result": "=\\sqrt{-4x\\left(x+1\\right)}",
"steps": [
{
"type": "step",
"primary": "Apply exponent rule: $$a^{b+c}=a^{b}a^{c}$$",
"secondary": [
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"result": "=-4xx-4x",
"meta": {
"practiceLink": "/practice/exponent-practice",
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},
{
"type": "step",
"primary": "Rewrite as",
"result": "=-4xx-1\\cdot\\:4x"
},
{
"type": "step",
"primary": "Factor out common term $$4x$$",
"result": "=-4x\\left(x+1\\right)",
"meta": {
"practiceLink": "/practice/factoring-practice",
"practiceTopic": "Factoring"
}
}
],
"meta": {
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},
{
"type": "step",
"primary": "Apply radical rule: $$\\sqrt[n]{ab}=\\sqrt[n]{a}\\sqrt[n]{b},\\:\\quad$$ assuming $$a\\ge0,\\:b\\ge0$$",
"result": "=\\sqrt{4}\\sqrt{-x\\left(x+1\\right)}",
"meta": {
"practiceLink": "/practice/radicals-practice",
"practiceTopic": "Radical Rules"
}
},
{
"type": "interim",
"title": "$$\\sqrt{4}=2$$",
"input": "\\sqrt{4}",
"result": "=2\\sqrt{-x\\left(x+1\\right)}",
"steps": [
{
"type": "step",
"primary": "Factor the number: $$4=2^{2}$$",
"result": "=\\sqrt{2^{2}}"
},
{
"type": "step",
"primary": "Apply radical rule: $$\\sqrt[n]{a^n}=a$$",
"secondary": [
"$$\\sqrt{2^{2}}=2$$"
],
"result": "=2",
"meta": {
"practiceLink": "/practice/radicals-practice",
"practiceTopic": "Radical Rules"
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],
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"interimType": "N/A"
}
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},
{
"type": "step",
"result": "=\\frac{1}{2\\sqrt{-x\\left(x+1\\right)}}"
}
],
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}
},
{
"type": "step",
"result": "=2\\cdot\\:\\frac{1}{2\\sqrt{-x\\left(x+1\\right)}}"
},
{
"type": "step",
"primary": "Multiply fractions: $$a\\cdot\\frac{b}{c}=\\frac{a\\:\\cdot\\:b}{c}$$",
"result": "=\\frac{1\\cdot\\:2}{2\\sqrt{-x\\left(x+1\\right)}}"
},
{
"type": "step",
"primary": "Cancel the common factor: $$2$$",
"result": "=\\frac{1}{\\sqrt{-x\\left(x+1\\right)}}"
}
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Solution
derivative of
Solution
Solution steps
Apply the chain rule:
Simplify
Graph
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Frequently Asked Questions (FAQ)
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The first derivative of y=arcsin(2x+1) is 1/(sqrt(-x(x+1)))