What is the derivative of y=\sqrt[3]{x} ?

The derivative of y=\sqrt[3]{x} is 1/(3x^{2/3)}

What is the first derivative of y=\sqrt[3]{x} ?

The first derivative of y=\sqrt[3]{x} is 1/(3x^{2/3)}

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derivative of

\frac{1}{3 x ^{\frac{2}{3}}}

Solution steps

Apply radical rule:

= \frac{d}{d x} (x^{\frac{1}{3}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{3} x^{\frac{1}{3} - 1}

Simplify

\frac{1}{3} x^{\frac{1}{3} - 1} : \frac{1}{3 x ^{\frac{2}{3}}}

= \frac{1}{3 x ^{\frac{2}{3}}}

(1, - 1)

5 x - 4 y = 8

y = 2 x

f (x) = e^{- x} ln (x), (1, 0)

(- 9, 0), (2, 5)

What is the derivative of y=\sqrt[3]{x} ?
The derivative of y=\sqrt[3]{x} is 1/(3x^{2/3)}
What is the first derivative of y=\sqrt[3]{x} ?
The first derivative of y=\sqrt[3]{x} is 1/(3x^{2/3)}