What is the derivative of f(x)=(3x-x^3+1)^4 ?

The derivative of f(x)=(3x-x^3+1)^4 is 4(3x-x^3+1)^3(-3x^2+3)

What is the first derivative of f(x)=(3x-x^3+1)^4 ?

The first derivative of f(x)=(3x-x^3+1)^4 is 4(3x-x^3+1)^3(-3x^2+3)

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derivative of

f (x) = (3 x - x^{3} + 1)^{4}

4 (3 x - x^{3} + 1)^{3} (- 3 x^{2} + 3)

Solution steps

\frac{d}{d x} ((3 x - x^{3} + 1)^{4})

Apply the chain rule:

4 (3 x - x^{3} + 1)^{3} \frac{d}{d x} (3 x - x^{3} + 1)

= 4 (3 x - x^{3} + 1)^{3} \frac{d}{d x} (3 x - x^{3} + 1)

\frac{d}{d x} (3 x - x^{3} + 1) = - 3 x^{2} + 3

= 4 (3 x - x^{3} + 1)^{3} (- 3 x^{2} + 3)

f (x) = x e^{x}

1 - e^{x}

f (x) = \frac{x}{2}

(- 3, - 3)

x - 1

What is the derivative of f(x)=(3x-x^3+1)^4 ?
The derivative of f(x)=(3x-x^3+1)^4 is 4(3x-x^3+1)^3(-3x^2+3)
What is the first derivative of f(x)=(3x-x^3+1)^4 ?
The first derivative of f(x)=(3x-x^3+1)^4 is 4(3x-x^3+1)^3(-3x^2+3)