What is the derivative of y=sec^2(x) ?

The derivative of y=sec^2(x) is 2sec^2(x)tan(x)

What is the first derivative of y=sec^2(x) ?

The first derivative of y=sec^2(x) is 2sec^2(x)tan(x)

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derivative of

y = sec^{2} (x)

2 sec^{2} (x) tan (x)

Solution steps

\frac{d}{d x} (sec^{2} (x))

Apply the chain rule:

2 sec (x) \frac{d}{d x} (sec (x))

= 2 sec (x) \frac{d}{d x} (sec (x))

\frac{d}{d x} (sec (x)) = sec (x) tan (x)

= 2 sec (x) sec (x) tan (x)

Simplify

2 sec (x) sec (x) tan (x) : 2 sec^{2} (x) tan (x)

= 2 sec^{2} (x) tan (x)

3 x

(- 6, 5), (- 3, - 3)

f (x) = x^{3}

e^{- x^{2}}

x e^{x}

What is the derivative of y=sec^2(x) ?
The derivative of y=sec^2(x) is 2sec^2(x)tan(x)
What is the first derivative of y=sec^2(x) ?
The first derivative of y=sec^2(x) is 2sec^2(x)tan(x)