What is the tangent of x^2+y^2+2xy=4,(1,1) ?

The tangent of x^2+y^2+2xy=4,(1,1) is y=-x+2

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tangent of x^2+y^2+2xy=4,(1,1)

tangent of

x^{2} + y^{2} + 2 x y = 4, (1, 1)

y = - x + 2

Solution steps

Find the slope of

x^{2} + y^{2} + 2 x y = 4 : \frac{d y}{d x} = - 1

Find the line with slope m=

- 1

and passing through

(1, 1) : y = - x + 2

y = - x + 2

y = - \frac{3}{4} x + 11

f = 5

f (x) = cos (2 x)

(0, 10), (- 9, 1)

f (x) = x^{2} + x - 5

What is the tangent of x^2+y^2+2xy=4,(1,1) ?
The tangent of x^2+y^2+2xy=4,(1,1) is y=-x+2