{
"query": {
"display": "tangent of $$f\\left(x\\right)=e^{-x}\\ln\\left(x\\right),\\:\\at\\:x=1$$",
"symbolab_question": "PRE_CALC#tangent f(x)=e^{-x}\\ln(x),\\at x=1"
},
"solution": {
"level": "PERFORMED",
"subject": "Calculus",
"topic": "Derivative Applications",
"subTopic": "Tangent",
"default": "y=\\frac{1}{e}x-\\frac{1}{e}",
"meta": {
"showVerify": true
}
},
"steps": {
"type": "interim",
"title": "Tangent line to $$f\\left(x\\right)=e^{-x}\\ln\\left(x\\right)$$, at $$x=1:{\\quad}y=\\frac{1}{e}x-\\frac{1}{e}$$",
"steps": [
{
"type": "interim",
"title": "Find the tangent point:$${\\quad}\\left(1,\\:0\\right)$$",
"steps": [
{
"type": "step",
"primary": "Plug $$x=1$$ into the equation $$f\\left(x\\right)=e^{-x}\\ln\\left(x\\right)$$",
"result": "f\\left(x\\right)=e^{-1}\\ln\\left(1\\right)"
},
{
"type": "step",
"primary": "Solve $$f\\left(x\\right)$$",
"result": "f\\left(x\\right)=0"
}
],
"meta": {
"interimType": "Tangent Find Tangent Point Title 0Eq"
}
},
{
"type": "interim",
"title": "Find the slope of $$f\\left(x\\right)=e^{-x}\\ln\\left(x\\right):{\\quad}\\frac{df\\left(x\\right)}{dx}=-e^{-x}\\ln\\left(x\\right)+\\frac{e^{-x}}{x}$$",
"input": "f\\left(x\\right)=e^{-x}\\ln\\left(x\\right)",
"steps": [
{
"type": "step",
"primary": "In order to find the slope of the function, take the derivative of $$e^{-x}\\ln\\left(x\\right)$$"
},
{
"type": "interim",
"title": "$$\\frac{d}{dx}\\left(e^{-x}\\ln\\left(x\\right)\\right)=-e^{-x}\\ln\\left(x\\right)+\\frac{e^{-x}}{x}$$",
"input": "\\frac{d}{dx}\\left(e^{-x}\\ln\\left(x\\right)\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the Product Rule: $$\\left(f{\\cdot}g\\right)'=f'{\\cdot}g+f{\\cdot}g'$$",
"secondary": [
"$$f=e^{-x},\\:g=\\ln\\left(x\\right)$$"
],
"result": "=\\frac{d}{dx}\\left(e^{-x}\\right)\\ln\\left(x\\right)+\\frac{d}{dx}\\left(\\ln\\left(x\\right)\\right)e^{-x}",
"meta": {
"practiceLink": "/practice/derivatives-practice#area=main&subtopic=Product%20Rule",
"practiceTopic": "Product Rule"
}
},
{
"type": "interim",
"title": "$$\\frac{d}{dx}\\left(e^{-x}\\right)=-e^{-x}$$",
"input": "\\frac{d}{dx}\\left(e^{-x}\\right)",
"steps": [
{
"type": "interim",
"title": "Apply the chain rule:$${\\quad}e^{-x}\\frac{d}{dx}\\left(-x\\right)$$",
"input": "\\frac{d}{dx}\\left(e^{-x}\\right)",
"result": "=e^{-x}\\frac{d}{dx}\\left(-x\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the chain rule: $$\\frac{df\\left(u\\right)}{dx}=\\frac{df}{du}\\cdot\\frac{du}{dx}$$",
"secondary": [
"$$f=e^{u},\\:\\:u=-x$$"
],
"result": "=\\frac{d}{du}\\left(e^{u}\\right)\\frac{d}{dx}\\left(-x\\right)",
"meta": {
"practiceLink": "/practice/derivatives-practice#area=main&subtopic=Chain%20Rule",
"practiceTopic": "Chain Rule"
}
},
{
"type": "interim",
"title": "$$\\frac{d}{du}\\left(e^{u}\\right)=e^{u}$$",
"input": "\\frac{d}{du}\\left(e^{u}\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the common derivative: $$\\frac{d}{du}\\left(e^{u}\\right)=e^{u}$$",
"result": "=e^{u}"
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYqCr3EWRZw3L4+rHTTdVG0Ok3hxk9aCfAWodBRxXgUexwx+RE9MtjN5hKMwTI7fffj/L0MoYg+CUn6oyL3EO7YrHahlpzKGY893KZ4T4i4Tv3RCXWsqiNx7T9zOhL5sYfw=="
}
},
{
"type": "step",
"result": "=e^{u}\\frac{d}{dx}\\left(-x\\right)"
},
{
"type": "step",
"primary": "Substitute back $$u=-x$$",
"result": "=e^{-x}\\frac{d}{dx}\\left(-x\\right)"
}
],
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"interimType": "Derivative Chain Rule 0Eq",
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}
},
{
"type": "interim",
"title": "$$\\frac{d}{dx}\\left(-x\\right)=-1$$",
"input": "\\frac{d}{dx}\\left(-x\\right)",
"steps": [
{
"type": "step",
"primary": "Take the constant out: $$\\left(a{\\cdot}f\\right)'=a{\\cdot}f'$$",
"result": "=-\\frac{dx}{dx}"
},
{
"type": "step",
"primary": "Apply the common derivative: $$\\frac{dx}{dx}=1$$",
"result": "=-1"
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives",
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}
},
{
"type": "step",
"result": "=e^{-x}\\left(-1\\right)"
},
{
"type": "step",
"primary": "Simplify",
"result": "=-e^{-x}",
"meta": {
"solvingClass": "Solver"
}
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives"
}
},
{
"type": "interim",
"title": "$$\\frac{d}{dx}\\left(\\ln\\left(x\\right)\\right)=\\frac{1}{x}$$",
"input": "\\frac{d}{dx}\\left(\\ln\\left(x\\right)\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the common derivative: $$\\frac{d}{dx}\\left(\\ln\\left(x\\right)\\right)=\\frac{1}{x}$$",
"result": "=\\frac{1}{x}"
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives",
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}
},
{
"type": "step",
"result": "=\\left(-e^{-x}\\right)\\ln\\left(x\\right)+\\frac{1}{x}e^{-x}"
},
{
"type": "interim",
"title": "Simplify $$\\left(-e^{-x}\\right)\\ln\\left(x\\right)+\\frac{1}{x}e^{-x}:{\\quad}-e^{-x}\\ln\\left(x\\right)+\\frac{e^{-x}}{x}$$",
"input": "\\left(-e^{-x}\\right)\\ln\\left(x\\right)+\\frac{1}{x}e^{-x}",
"result": "=-e^{-x}\\ln\\left(x\\right)+\\frac{e^{-x}}{x}",
"steps": [
{
"type": "step",
"primary": "Remove parentheses: $$\\left(-a\\right)=-a$$",
"result": "=-e^{-x}\\ln\\left(x\\right)+\\frac{1}{x}e^{-x}"
},
{
"type": "interim",
"title": "$$\\frac{1}{x}e^{-x}=\\frac{e^{-x}}{x}$$",
"input": "\\frac{1}{x}e^{-x}",
"steps": [
{
"type": "step",
"primary": "Multiply fractions: $$a\\cdot\\frac{b}{c}=\\frac{a\\:\\cdot\\:b}{c}$$",
"result": "=\\frac{1\\cdot\\:e^{-x}}{x}"
},
{
"type": "step",
"primary": "Multiply: $$1\\cdot\\:e^{-x}=e^{-x}$$",
"result": "=\\frac{e^{-x}}{x}"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
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},
{
"type": "step",
"result": "=-e^{-x}\\ln\\left(x\\right)+\\frac{e^{-x}}{x}"
}
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],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives"
}
},
{
"type": "step",
"result": "-e^{-x}\\ln\\left(x\\right)+\\frac{e^{-x}}{x}"
}
],
"meta": {
"interimType": "Slope Equation Top 1Eq",
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}
},
{
"type": "interim",
"title": "$$EN:\\:Title\\:General\\:Equation\\:Slope\\:At\\:Point\\:2Eq:{\\quad}m=\\frac{1}{e}$$",
"steps": [
{
"type": "step",
"primary": "Plug $$x=1$$ into the equation $$-e^{-x}\\ln\\left(x\\right)+\\frac{e^{-x}}{x}$$",
"result": "-e^{-1}\\ln\\left(1\\right)+\\frac{e^{-1}}{1}"
},
{
"type": "interim",
"title": "Simplify $$-e^{-1}\\ln\\left(1\\right)+\\frac{e^{-1}}{1}:{\\quad}\\frac{1}{e}$$",
"input": "-e^{-1}\\ln\\left(1\\right)+\\frac{e^{-1}}{1}",
"result": "=\\frac{1}{e}",
"steps": [
{
"type": "step",
"primary": "Apply rule $$\\frac{a}{1}=a$$",
"secondary": [
"$$\\frac{e^{-1}}{1}=e^{-1}$$"
],
"result": "=-e^{-1}\\ln\\left(1\\right)+e^{-1}"
},
{
"type": "interim",
"title": "$$e^{-1}\\ln\\left(1\\right)=0$$",
"input": "e^{-1}\\ln\\left(1\\right)",
"steps": [
{
"type": "interim",
"title": "Simplify $$\\ln\\left(1\\right):{\\quad}0$$",
"input": "\\ln\\left(1\\right)",
"result": "=0\\cdot\\:e^{-1}",
"steps": [
{
"type": "step",
"primary": "Apply log rule: $$\\log_a\\left(1\\right)=0$$",
"result": "=0",
"meta": {
"practiceLink": "/practice/logarithms-practice",
"practiceTopic": "Expand FOIL"
}
}
],
"meta": {
"interimType": "Algebraic Manipulation Simplify Title 1Eq"
}
},
{
"type": "step",
"primary": "Apply rule $$0\\cdot\\:a=0$$",
"result": "=0"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7ExISlLtcJp21c7LeXLGv6i061ljBSPJeENOw2efoSWtRZPRrfkNDmi+szkABFipUn8cp9RqO912RyV+lrdCBCc7RuMQ+KShx/NfZbf2mzeQ="
}
},
{
"type": "step",
"result": "=-0+e^{-1}"
},
{
"type": "interim",
"title": "Simplify",
"input": "-0+e^{-1}",
"steps": [
{
"type": "step",
"primary": "Apply exponent rule: $$a^{-1}=\\frac{1}{a}$$",
"secondary": [
"$$e^{-1}=\\frac{1}{e}$$"
],
"result": "=-0+\\frac{1}{e}",
"meta": {
"practiceLink": "/practice/exponent-practice",
"practiceTopic": "Expand FOIL"
}
},
{
"type": "step",
"primary": "$$-0+\\frac{1}{e}=\\frac{1}{e}$$",
"result": "=\\frac{1}{e}"
}
],
"meta": {
"interimType": "Generic Simplify 0Eq"
}
},
{
"type": "step",
"result": "=\\frac{1}{e}"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Generic Simplify Specific 1Eq"
}
},
{
"type": "step",
"result": "m=\\frac{1}{e}"
}
],
"meta": {
"interimType": "General Equation Slope At Point 2Eq"
}
},
{
"type": "interim",
"title": "Find the line with slope m=$$\\frac{1}{e}$$ and passing through $$\\left(1,\\:0\\right):{\\quad}y=\\frac{1}{e}x-\\frac{1}{e}$$",
"steps": [
{
"type": "step",
"primary": "Compute the line equation $$\\mathbf{y=mx+b}$$ for slope m=$$\\frac{1}{e}$$ and passing through $$\\left(1,\\:0\\right)$$"
},
{
"type": "interim",
"title": "Compute the $$y$$ intercept:$${\\quad}b=-\\frac{1}{e}$$",
"steps": [
{
"type": "step",
"primary": "Plug the slope $$\\frac{1}{e}$$ into $$y=mx+b$$",
"result": "y=\\frac{1}{e}x+b"
},
{
"type": "step",
"primary": "Plug in $$\\left(1,\\:0\\right)$$: $$\\quad\\:x=1,\\:y=0$$",
"result": "0=\\frac{1}{e}\\cdot\\:1+b"
},
{
"type": "step",
"primary": "Isolate $$b$$"
},
{
"type": "interim",
"title": "$$0=\\frac{1}{e}\\cdot\\:1+b{\\quad:\\quad}b=-\\frac{1}{e}$$",
"input": "0=\\frac{1}{e}\\cdot\\:1+b",
"steps": [
{
"type": "step",
"primary": "Switch sides",
"result": "\\frac{1}{e}\\cdot\\:1+b=0"
},
{
"type": "step",
"primary": "Multiply: $$\\frac{1}{e}\\cdot\\:1=\\frac{1}{e}$$",
"result": "\\frac{1}{e}+b=0"
},
{
"type": "interim",
"title": "Move $$\\frac{1}{e}\\:$$to the right side",
"input": "\\frac{1}{e}+b=0",
"result": "b=-\\frac{1}{e}",
"steps": [
{
"type": "step",
"primary": "Subtract $$\\frac{1}{e}$$ from both sides",
"result": "\\frac{1}{e}+b-\\frac{1}{e}=0-\\frac{1}{e}"
},
{
"type": "step",
"primary": "Simplify",
"result": "b=-\\frac{1}{e}"
}
],
"meta": {
"interimType": "Move to the Right Title 1Eq",
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],
"meta": {
"solvingClass": "Equations",
"interimType": "Equations"
}
},
{
"type": "step",
"result": "b=-\\frac{1}{e}"
}
],
"meta": {
"interimType": "Line Equation Find Intersection From Point 0Eq"
}
},
{
"type": "step",
"primary": "Construct the line equation $$\\mathbf{y=mx+b}$$ where $$\\mathbf{m}=\\frac{1}{e}$$ and $$\\mathbf{b}=-\\frac{1}{e}$$",
"result": "y=\\frac{1}{e}x-\\frac{1}{e}"
}
],
"meta": {
"interimType": "Line Equation Slope Point 6Eq"
}
},
{
"type": "step",
"result": "y=\\frac{1}{e}x-\\frac{1}{e}"
}
],
"meta": {
"solvingClass": "PreCalc"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "x",
"plotRequest": "tangent f(x)=e^{-x}\\ln(x),\\at x=1"
},
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}
},
"meta": {
"showVerify": true
}
}
Solution
tangent of
Solution
Solution steps
Find the tangent point:
Find the slope of
Find the line with slope m= and passing through
Graph
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Frequently Asked Questions (FAQ)
What is the tangent of f(x)=e^{-x}ln(x),\at x=1 ?
The tangent of f(x)=e^{-x}ln(x),\at x=1 is y= 1/e x-1/e