What is the derivative of f(x)=x^2-4x ?

The derivative of f(x)=x^2-4x is 2x-4

What is the first derivative of f(x)=x^2-4x ?

The first derivative of f(x)=x^2-4x is 2x-4

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derivative of

f (x) = x^{2} - 4 x

2 x - 4

Solution steps

\frac{d}{d x} (x^{2} - 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (4 x)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

= 2 x - 4

(- 3, \frac{5 π}{6})

x = 7

(9, \frac{5 π}{6})

y = x^{\frac{3}{2}}

f = 3

What is the derivative of f(x)=x^2-4x ?
The derivative of f(x)=x^2-4x is 2x-4
What is the first derivative of f(x)=x^2-4x ?
The first derivative of f(x)=x^2-4x is 2x-4