What is (4)^2-4(1)(4) ?

The solution to (4)^2-4(1)(4) is 0

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(4)^2-4(1)(4)

(4)^{2} - 4 (1) (4)

0

Solution steps

(4)^{2} - 4 (1) (4)

Follow the PEMDAS order of operations

Calculate exponents

(4)^{2} : 16

(4)^{2}

(4)^{2} = 16

= 16

= 16 - 4 (1) (4)

Multiply and divide (left to right)

4 (1) (4) : 16

4 (1) (4)

4 (1) = 4

4 (1)

Apply rule:

(a) = a

(1) = 1

= 4 \cdot 1

Multiply the numbers:

4 \cdot 1 = 4

= 4

= 4 (4)

4 (4) = 16

4 (4)

Apply rule:

(a) = a

(4) = 4

= 4 \cdot 4

Multiply the numbers:

4 \cdot 4 = 16

= 16

= 16

= 16 - 16

Add and subtract (left to right)

16 - 16 : 0

16 - 16

16 - 16 = 0

= 0

= 0

2 (4 + 8) \times 8 + 2 \times 4 \times 8

6^{4} - 8 (6)^{3}

- 12 + (- 4) - 9 + 0

4 - (2 (3 - 5) - (5 - 2) (- 7 + 4 \div 2))

- 2^{2} - 9