What is (-3)^2+6(-3)+3 ?

The solution to (-3)^2+6(-3)+3 is -6

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(-3)^2+6(-3)+3

(- 3)^{2} + 6 (- 3) + 3

- 6

Solution steps

(- 3)^{2} + 6 (- 3) + 3

Follow the PEMDAS order of operations

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= 9 + 6 (- 3) + 3

Multiply and divide (left to right)

6 (- 3) : - 18

6 (- 3)

Apply rule

a \cdot (- b) = - a \cdot b

6 (- 3) = - 6 \cdot 3 = - 18

= - 18

= 9 - 18 + 3

Add and subtract (left to right)

9 - 18 + 3 : - 6

9 - 18 + 3

9 - 18 = - 9

= - 9 + 3

- 9 + 3 = - 6

= - 6

= - 6

(3 + 6) \times 2

- ((- 8 \div 2) + (4 \times (- 24))) \div (- 3 + (- 1))

3 0^{2} + 30 + 4

(16 - 4^{2}) \times 12

80 \div 2 + [6 \times 3 + 5] - (4 \times 2 + 5)