What is 5^2+(3)^2+(-2)^3 ?

The solution to 5^2+(3)^2+(-2)^3 is 26

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5^2+(3)^2+(-2)^3

5^{2} + (3)^{2} + (- 2)^{3}

26

Solution steps

5^{2} + (3)^{2} + (- 2)^{3}

Follow the PEMDAS order of operations

Calculate exponents

5^{2} : 25

5^{2}

5^{2} = 25

= 25

= 25 + (3)^{2} + (- 2)^{3}

Calculate exponents

(3)^{2} : 9

(3)^{2}

(3)^{2} = 9

= 9

= 25 + 9 + (- 2)^{3}

Calculate exponents

(- 2)^{3} : - 8

(- 2)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 2)^{3} = - 2^{3} = - 8

= - 8

= 25 + 9 - 8

Add and subtract (left to right)

25 + 9 - 8 : 26

25 + 9 - 8

25 + 9 = 34

= 34 - 8

34 - 8 = 26

= 26

= 26

- 8^{2} - 2 1^{2}

3 + 2 \times 4 - (- 1)^{2}

3^{5} \cdot 4

- 20 + 11 (11)

\frac{4 + 12}{2 ( 4 ) - 1}