What is 4-2(5-2(4-2))\div 24-2(5-2(4-2))\div 2 ?

The solution to 4-2(5-2(4-2))\div 24-2(5-2(4-2))\div 2 is 2 11/12

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Popular Pre Algebra >

4-2(5-2(4-2))\div 24-2(5-2(4-2))\div 2

Solution

4 - 2 (5 - 2 (4 - 2)) \div 24 - 2 (5 - 2 (4 - 2)) \div 2

Solution

2 \frac{11}{12}

Decimal

2.91666 \dots

Solution steps

4 - 2 (5 - 2 (4 - 2)) \div 24 - 2 (5 - 2 (4 - 2)) \div 2

Follow the PEMDAS order of operations

Calculate within parentheses

(5 - 2 (4 - 2)) : 1

5 - 2 (4 - 2)

Calculate within parentheses

(4 - 2) : 2

4 - 2

4 - 2 = 2

= 2

= 5 - 2 \cdot 2

Multiply and divide (left to right)

2 \cdot 2 : 4

2 \cdot 2

2 \cdot 2 = 4

= 4

= 5 - 4

Add and subtract (left to right)

5 - 4 : 1

5 - 4

5 - 4 = 1

= 1

= 1

= 4 - 2 \cdot 1 \div 24 - 2 (5 - 2 (4 - 2)) \div 2

Calculate within parentheses

(5 - 2 (4 - 2)) : 1

5 - 2 (4 - 2)

Calculate within parentheses

(4 - 2) : 2

4 - 2

4 - 2 = 2

= 2

= 5 - 2 \cdot 2

Multiply and divide (left to right)

2 \cdot 2 : 4

2 \cdot 2

2 \cdot 2 = 4

= 4

= 5 - 4

Add and subtract (left to right)

5 - 4 : 1

5 - 4

5 - 4 = 1

= 1

= 1

= 4 - 2 \cdot 1 \div 24 - 2 \cdot 1 \div 2

Multiply and divide (left to right)

2 \cdot 1 \div 24 : \frac{2}{24}

2 \cdot 1 \div 24

2 \cdot 1 = 2

= 2 \div 24

2 \div 24 = \frac{2}{24}

= \frac{2}{24}

= 4 - \frac{2}{24} - 2 \cdot 1 \div 2

Multiply and divide (left to right)

2 \cdot 1 \div 2 : 1

2 \cdot 1 \div 2

2 \cdot 1 = 2

= 2 \div 2

2 \div 2 = 1

= 1

= 4 - \frac{2}{24} - 1

Add and subtract (left to right)

4 - \frac{2}{24} - 1 : \frac{35}{12}

4 - \frac{2}{24} - 1

4 - \frac{2}{24} = \frac{47}{12}

4 - \frac{2}{24}

Cancel

\frac{2}{24} : \frac{1}{12}

\frac{2}{24}

Cancel the common factor:

2

= \frac{1}{12}

= 4 - \frac{1}{12}

Convert element to fraction:

4 = \frac{4 \cdot 12}{12}

= \frac{4 \cdot 12}{12} - \frac{1}{12}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{4 \cdot 12 - 1}{12}

4 \cdot 12 - 1 = 47

4 \cdot 12 - 1

Multiply the numbers:

4 \cdot 12 = 48

= 48 - 1

Subtract the numbers:

48 - 1 = 47

= 47

= \frac{47}{12}

= \frac{47}{12} - 1

\frac{47}{12} - 1 = \frac{35}{12}

\frac{47}{12} - 1

Convert element to fraction:

1 = \frac{1 \cdot 12}{12}

= - \frac{1 \cdot 12}{12} + \frac{47}{12}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 1 \cdot 12 + 47}{12}

- 1 \cdot 12 + 47 = 35

- 1 \cdot 12 + 47

Multiply the numbers:

1 \cdot 12 = 12

= - 12 + 47

Add/Subtract the numbers:

- 12 + 47 = 35

= 35

= \frac{35}{12}

= \frac{35}{12}

= \frac{35}{12}

Convert improper fractions to mixed numbers:

\frac{35}{12} = 2 \frac{11}{12}

\frac{35}{12} = 2

Remainder

11

\frac{35}{12}

Write the problem in long division format

12 \overline{∣ 35}

Divide

35

12

to get

2

Divide

35

12

to get

2

2 12 \overline{∣ 35}

Multiply the quotient digit

(2)

by the divisor

12

2 12 \overline{∣ 35} \underline{24}

Subtract

24

from

35

2 12 \overline{∣ 35} \underline{24} 11

2 12 \overline{∣ 35} \underline{24} 11

The solution for Long Division of

\frac{35}{12}

2

with remainder of

11

2 Remainder 11

Convert to mixed number: Quotient

\frac{Remainder}{Divisor}

\frac{35}{12} = 2 \frac{11}{12}

= 2 \frac{11}{12}

= 2 \frac{11}{12}

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Frequently Asked Questions (FAQ)

What is 4-2(5-2(4-2))\div 24-2(5-2(4-2))\div 2 ?
The solution to 4-2(5-2(4-2))\div 24-2(5-2(4-2))\div 2 is 2 11/12

4-2(5-2(4-2))\div 24-2(5-2(4-2))\div 2

Solution

Solution

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Frequently Asked Questions (FAQ)

What is 4-2(5-2(4-2))\div 24-2(5-2(4-2))\div 2 ?

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