What is 30\div 120\times 100 ?

The solution to 30\div 120\times 100 is 25

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30\div 120\times 100

30 \div 120 \times 100

25

Solution steps

30 \div 120 \times 100

Follow the PEMDAS order of operations

Multiply and divide (left to right)

30 \div 120 = \frac{30}{120}

= \frac{30}{120} \times 100

\frac{30}{120} \times 100 = 25

\frac{30}{120} \cdot 100

Cancel the numbers:

\frac{30}{120} = \frac{1}{4}

= \frac{1}{4} \cdot 100

\frac{1}{4} \cdot 100 = 25

\frac{1}{4} \cdot 100

Convert element to fraction:

100 = \frac{100}{1}

= \frac{1}{4} \cdot \frac{100}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{1 \cdot 100}{4 \cdot 1}

\frac{1 \cdot 100}{4 \cdot 1} = 25

\frac{1 \cdot 100}{4 \cdot 1}

\frac{1 \cdot 100}{4 \cdot 1} = \frac{100}{4}

\frac{1 \cdot 100}{4 \cdot 1}

Multiply the numbers:

1 \cdot 100 = 100

= \frac{100}{4 \cdot 1}

Multiply the numbers:

4 \cdot 1 = 4

= \frac{100}{4}

= \frac{100}{4}

Divide the numbers:

\frac{100}{4} = 25

= 25

= 25

= 25

= 25

4^{2} - (- 4^{2})

1 - 2 (\frac{1}{3})

2^{2} \cdot [3^{2} - (4 + 8)] + (4 \div 2)

1 4^{2} + 5^{2}

8 \times + 3 + 6 - 5 \times (- 2) + 4