What is -(-2)^2-5(2)+1 ?

The solution to -(-2)^2-5(2)+1 is -13

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-(-2)^2-5(2)+1

- (- 2)^{2} - 5 (2) + 1

- 13

Solution steps

- (- 2)^{2} - 5 (2) + 1

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= - 4 - 5 (2) + 1

Multiply and divide (left to right)

5 (2) : 10

5 (2)

Apply rule:

(a) = a

(2) = 2

= 5 \cdot 2

Multiply the numbers:

5 \cdot 2 = 10

= 10

= - 4 - 10 + 1

Add and subtract (left to right)

- 4 - 10 + 1 : - 13

- 4 - 10 + 1

- 4 - 10 = - 14

= - 14 + 1

- 14 + 1 = - 13

= - 13

= - 13

8 - 3 - 5 \times 3 \times 9

\frac{16}{3} + 2 - \frac{2}{3} + 1

1 - (3 \times 0)

\frac{1}{2} (5)^{0}

\frac{1}{2} (5)^{2}