What is (-3)(-4)+(-1)(+2)\div (+2)(-2) ?

The solution to (-3)(-4)+(-1)(+2)\div (+2)(-2) is 14

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(-3)(-4)+(-1)(+2)\div (+2)(-2)

(- 3) (- 4) + (- 1) (+ 2) \div (+ 2) (- 2)

14

Solution steps

(- 3) (- 4) + (- 1) (2) \div (2) (- 2)

Follow the PEMDAS order of operations

Multiply and divide (left to right)

(- 3) (- 4) : 12

(- 3) (- 4)

Apply rule

(- a) \cdot (- b) = a \cdot b

(- 3) (- 4) = 3 \cdot 4 = 12

= 12

= 12 + (- 1) (2) \div (2) (- 2)

Multiply and divide (left to right)

(- 1) (2) \div (2) (- 2) : - 2

(- 1) (2) \div (2) (- 2)

Apply rule

(- a) \cdot (b) = - a \cdot b

(- 1) (2) = - 1 \cdot 2 = - 2

= - 2 \div (2) (- 2)

2 \div (2) = \frac{2}{( 2 )}

= \frac{2}{( 2 )} (- 2)

\frac{2}{( 2 )} (- 2) = - 2

\frac{2}{( 2 )} (- 2)

Apply rule

a \cdot (- b) = - a \cdot b

\frac{2}{( 2 )} (- 2) = - \frac{2}{( 2 )} \cdot 2

Convert element to fraction:

2 = \frac{2}{1}

= - \frac{2}{2} \cdot \frac{2}{1}

Cross-cancel common factor:

2

= - \frac{2}{1}

Divide the numbers:

\frac{2}{1} = 2

= - 2

= - 2

= 12 - (- 2)

Add and subtract (left to right)

12 - (- 2) : 14

12 - (- 2)

Apply rule

- (- a) = + a

- (- 2) = + 2

= 12 + 2

12 + 2 = 14

= 14

= 14

- (3 \times (- 7))

[4 + 2 \frac{2}{5}] \times \frac{1}{5}

1 6^{2} - 7^{2}

3 \times 5 + (3 \times 2 - 8) \times 5 - 3

5 (0) + 4

What is (-3)(-4)+(-1)(+2)\div (+2)(-2) ?
The solution to (-3)(-4)+(-1)(+2)\div (+2)(-2) is 14