What is [15+(8-3)5]\div [(8-2)\div 2+7] ?

The solution to [15+(8-3)5]\div [(8-2)\div 2+7] is 4

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[15+(8-3)5]\div [(8-2)\div 2+7]

[15 + (8 - 3) 5] \div [(8 - 2) \div 2 + 7]

4

Solution steps

[15 + (8 - 3) \cdot 5] \div [(8 - 2) \div 2 + 7]

Follow the PEMDAS order of operations

Calculate within parentheses

[15 + (8 - 3) 5] : 40

15 + (8 - 3) \cdot 5

Calculate within parentheses

(8 - 3) : 5

8 - 3

8 - 3 = 5

= 5

= 15 + 5 \cdot 5

Multiply and divide (left to right)

5 \cdot 5 : 25

5 \cdot 5

5 \cdot 5 = 25

= 25

= 15 + 25

Add and subtract (left to right)

15 + 25 : 40

15 + 25

15 + 25 = 40

= 40

= 40

= 40 \div [(8 - 2) \div 2 + 7]

Calculate within parentheses

[(8 - 2) \div 2 + 7] : 10

(8 - 2) \div 2 + 7

Calculate within parentheses

(8 - 2) : 6

8 - 2

8 - 2 = 6

= 6

= 6 \div 2 + 7

Multiply and divide (left to right)

6 \div 2 : 3

6 \div 2

6 \div 2 = 3

= 3

= 3 + 7

Add and subtract (left to right)

3 + 7 : 10

3 + 7

3 + 7 = 10

= 10

= 10

= 40 \div 10

Multiply and divide (left to right)

40 \div 10 : 4

40 \div 10

40 \div 10 = 4

= 4

= 4

6^{2} + 2 \times 3 - 5 + 3

5/8 - 1/2 + 2/3 - 5/6

2 \times 5^{3}

- 6^{2} + 5 (- 6) - 3

(- 1)^{2} + 5 \times (- 6)

What is [15+(8-3)5]\div [(8-2)\div 2+7] ?
The solution to [15+(8-3)5]\div [(8-2)\div 2+7] is 4