What is 6+(4-((17-(4\times 4))+3)-5) ?

The solution to 6+(4-((17-(4\times 4))+3)-5) is 1

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6+(4-((17-(4\times 4))+3)-5)

6 + (4 - ((17 - (4 \cdot 4)) + 3) - 5)

1

Solution steps

6 + (4 - ((17 - (4 \cdot 4)) + 3) - 5)

Follow the PEMDAS order of operations

Calculate within parentheses

(4 - ((17 - (4 \cdot 4)) + 3) - 5) : - 5

4 - ((17 - (4 \cdot 4)) + 3) - 5

Calculate within parentheses

((17 - (4 \cdot 4)) + 3) : 4

(17 - (4 \cdot 4)) + 3

Calculate within parentheses

(17 - (4 \cdot 4)) : 1

17 - (4 \cdot 4)

Calculate within parentheses

(4 \cdot 4) : 16

4 \cdot 4

4 \cdot 4 = 16

= 16

= 17 - 16

Add and subtract (left to right)

17 - 16 : 1

17 - 16

17 - 16 = 1

= 1

= 1

= 1 + 3

Add and subtract (left to right)

1 + 3 : 4

1 + 3

1 + 3 = 4

= 4

= 4

= 4 - 4 - 5

Add and subtract (left to right)

4 - 4 - 5 : - 5

4 - 4 - 5

4 - 4 = 0

= 0 - 5

0 - 5 = - 5

= - 5

= - 5

= 6 - 5

Add and subtract (left to right)

6 - 5 : 1

6 - 5

6 - 5 = 1

= 1

= 1

- (17) + (- 4) + (- 3) - (- 20)

2 + 3 \times 4 - ((- 3) 2 + 4 - 3 \times 5)

1 \div 3 + 2 \div 5

3 (8 \times 5^{2}) + 6

2^{2} + 4^{3} + 3^{3} \times 2^{2}

What is 6+(4-((17-(4\times 4))+3)-5) ?
The solution to 6+(4-((17-(4\times 4))+3)-5) is 1