What is 48\div [5*3-2*(6-10)-17] ?

The solution to 48\div [5*3-2*(6-10)-17] is 8

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48\div [53-2(6-10)-17]

48 \div [5 \cdot 3 - 2 \cdot (6 - 10) - 17]

8

Solution steps

48 \div [5 \cdot 3 - 2 (6 - 10) - 17]

Follow the PEMDAS order of operations

Calculate within parentheses

[5 \cdot 3 - 2 \cdot (6 - 10) - 17] : 6

5 \cdot 3 - 2 (6 - 10) - 17

Calculate within parentheses

(6 - 10) : - 4

6 - 10

6 - 10 = - 4

= - 4

= 5 \cdot 3 - 2 (- 4) - 17

Multiply and divide (left to right)

5 \cdot 3 : 15

5 \cdot 3

5 \cdot 3 = 15

= 15

= 15 - 2 (- 4) - 17

Multiply and divide (left to right)

2 (- 4) : - 8

2 (- 4)

Apply rule

a \cdot (- b) = - a \cdot b

2 (- 4) = - 2 \cdot 4 = - 8

= - 8

= 15 - (- 8) - 17

Add and subtract (left to right)

15 - (- 8) - 17 : 6

15 - (- 8) - 17

Apply rule

- (- a) = + a

- (- 8) = + 8

= 15 + 8 - 17

15 + 8 = 23

= 23 - 17

23 - 17 = 6

= 6

= 6

= 48 \div 6

Multiply and divide (left to right)

48 \div 6 : 8

48 \div 6

48 \div 6 = 8

= 8

= 8

- 1 (- 1^{2} + 1)

48 \times 18 \div 3

5 3^{2} - 2 8^{2}

3 (4 - 2)^{2} - 7

(10 + 2 - 2) \times 6 - 1

What is 48\div [5*3-2*(6-10)-17] ?
The solution to 48\div [5*3-2*(6-10)-17] is 8