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Popular Pre Algebra >

1/2 (1)^3+5(1)^2-2(1)

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Solution

21​(1)3+5(1)2−2(1)

Solution

321​
+1
Decimal
3.5
Solution steps
21​(1)3+5(1)2−2(1)
Follow the PEMDAS order of operations
Calculate exponents (1)3:1
(1)3
(1)3=1=1
=21​⋅1+5(1)2−2(1)
Calculate exponents (1)2:1
(1)2
(1)2=1=1
=21​⋅1+5⋅1−2(1)
Multiply and divide (left to right) 21​⋅1:21​
21​⋅1
21​⋅1=21​=21​
=21​+5⋅1−2(1)
Multiply and divide (left to right) 5⋅1:5
5⋅1
5⋅1=5=5
=21​+5−2(1)
Multiply and divide (left to right) 2(1):2
2(1)
Apply rule: (a)=a(1)=1=2⋅1
Multiply the numbers: 2⋅1=2=2
=21​+5−2
Add and subtract (left to right) 21​+5−2:27​
21​+5−2
21​+5=211​
21​+5
Convert element to fraction: 5=25⋅2​=25⋅2​+21​
Since the denominators are equal, combine the fractions: ca​±cb​=ca±b​=25⋅2+1​
5⋅2+1=11
5⋅2+1
Multiply the numbers: 5⋅2=10=10+1
Add the numbers: 10+1=11=11
=211​
=211​−2
211​−2=27​
211​−2
Convert element to fraction: 2=22⋅2​=−22⋅2​+211​
Since the denominators are equal, combine the fractions: ca​±cb​=ca±b​=2−2⋅2+11​
−2⋅2+11=7
−2⋅2+11
Multiply the numbers: 2⋅2=4=−4+11
Add/Subtract the numbers: −4+11=7=7
=27​
=27​
=27​
Convert improper fractions to mixed numbers:27​=321​
27​=3Remainder1
27​
Write the problem in long division format2∣7​​
Divide 7by 2to get 3
Divide 7by 2to get 332∣7​​
Multiply the quotient digit (3)by the divisor 232∣7​6​​
Subtract 6from 732∣7​6​1​
32∣7​6​1​
The solution for Long Division of 27​is 3with remainder of 13Remainder1
Convert to mixed number: QuotientDivisorRemainder​27​=321​
=321​
=321​

Popular Examples

(0)^2-5(0)+1-11(2)+(-11)+910^2-2× 4-16+5-3[(-4-7)-(-4)]-(3-19)

Frequently Asked Questions (FAQ)

  • What is 1/2 (1)^3+5(1)^2-2(1) ?

    The solution to 1/2 (1)^3+5(1)^2-2(1) is 3 1/2

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